2019-10-27 23:52:34 +00:00
|
|
|
"""
|
|
|
|
The Fibonacci sequence is defined by the recurrence relation:
|
|
|
|
|
2024-04-22 19:51:47 +00:00
|
|
|
Fn = Fn-1 + Fn-2, where F1 = 1 and F2 = 1.
|
2019-10-27 23:52:34 +00:00
|
|
|
|
|
|
|
Hence the first 12 terms will be:
|
|
|
|
|
|
|
|
F1 = 1
|
|
|
|
F2 = 1
|
|
|
|
F3 = 2
|
|
|
|
F4 = 3
|
|
|
|
F5 = 5
|
|
|
|
F6 = 8
|
|
|
|
F7 = 13
|
|
|
|
F8 = 21
|
|
|
|
F9 = 34
|
|
|
|
F10 = 55
|
|
|
|
F11 = 89
|
|
|
|
F12 = 144
|
|
|
|
|
|
|
|
The 12th term, F12, is the first term to contain three digits.
|
|
|
|
|
|
|
|
What is the index of the first term in the Fibonacci sequence to contain 1000
|
|
|
|
digits?
|
|
|
|
"""
|
|
|
|
|
|
|
|
|
2020-10-07 03:57:25 +00:00
|
|
|
def solution(n: int = 1000) -> int:
|
2019-10-27 23:52:34 +00:00
|
|
|
"""Returns the index of the first term in the Fibonacci sequence to contain
|
|
|
|
n digits.
|
|
|
|
|
|
|
|
>>> solution(1000)
|
|
|
|
4782
|
|
|
|
>>> solution(100)
|
|
|
|
476
|
|
|
|
>>> solution(50)
|
|
|
|
237
|
|
|
|
>>> solution(3)
|
|
|
|
12
|
|
|
|
"""
|
|
|
|
f1, f2 = 1, 1
|
|
|
|
index = 2
|
|
|
|
while True:
|
|
|
|
i = 0
|
|
|
|
f = f1 + f2
|
|
|
|
f1, f2 = f2, f
|
|
|
|
index += 1
|
2022-10-13 16:03:06 +00:00
|
|
|
for _ in str(f):
|
2019-10-27 23:52:34 +00:00
|
|
|
i += 1
|
|
|
|
if i == n:
|
|
|
|
break
|
|
|
|
return index
|
|
|
|
|
|
|
|
|
|
|
|
if __name__ == "__main__":
|
|
|
|
print(solution(int(str(input()).strip())))
|