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40 lines
1012 B
Python
40 lines
1012 B
Python
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"""
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Problem:
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The sum of the squares of the first ten natural numbers is,
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1^2 + 2^2 + ... + 10^2 = 385
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The square of the sum of the first ten natural numbers is,
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(1 + 2 + ... + 10)^2 = 552 = 3025
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Hence the difference between the sum of the squares of the first ten natural
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numbers and the square of the sum is 3025 − 385 = 2640.
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Find the difference between the sum of the squares of the first N natural
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numbers and the square of the sum.
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"""
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def solution(n):
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"""Returns the difference between the sum of the squares of the first n
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natural numbers and the square of the sum.
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>>> solution(10)
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2640
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>>> solution(15)
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13160
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>>> solution(20)
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41230
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>>> solution(50)
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1582700
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>>> solution(100)
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25164150
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"""
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sum_of_squares = n * (n + 1) * (2 * n + 1) / 6
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square_of_sum = (n * (n + 1) / 2) ** 2
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return int(square_of_sum - sum_of_squares)
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if __name__ == "__main__":
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print(solution(int(input("Enter a number: ").strip())))
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