mirror of
https://github.com/TheAlgorithms/Python.git
synced 2024-12-25 04:30:15 +00:00
63 lines
1.6 KiB
Python
63 lines
1.6 KiB
Python
|
"""
|
||
|
Project Euler 62
|
||
|
https://projecteuler.net/problem=62
|
||
|
|
||
|
The cube, 41063625 (345^3), can be permuted to produce two other cubes:
|
||
|
56623104 (384^3) and 66430125 (405^3). In fact, 41063625 is the smallest cube
|
||
|
which has exactly three permutations of its digits which are also cube.
|
||
|
|
||
|
Find the smallest cube for which exactly five permutations of its digits are
|
||
|
cube.
|
||
|
"""
|
||
|
|
||
|
from collections import defaultdict
|
||
|
|
||
|
|
||
|
def solution(max_base: int = 5) -> int:
|
||
|
"""
|
||
|
Iterate through every possible cube and sort the cube's digits in
|
||
|
ascending order. Sorting maintains an ordering of the digits that allows
|
||
|
you to compare permutations. Store each sorted sequence of digits in a
|
||
|
dictionary, whose key is the sequence of digits and value is a list of
|
||
|
numbers that are the base of the cube.
|
||
|
|
||
|
Once you find 5 numbers that produce the same sequence of digits, return
|
||
|
the smallest one, which is at index 0 since we insert each base number in
|
||
|
ascending order.
|
||
|
|
||
|
>>> solution(2)
|
||
|
125
|
||
|
>>> solution(3)
|
||
|
41063625
|
||
|
"""
|
||
|
freqs = defaultdict(list)
|
||
|
num = 0
|
||
|
|
||
|
while True:
|
||
|
digits = get_digits(num)
|
||
|
freqs[digits].append(num)
|
||
|
|
||
|
if len(freqs[digits]) == max_base:
|
||
|
base = freqs[digits][0] ** 3
|
||
|
return base
|
||
|
|
||
|
num += 1
|
||
|
|
||
|
|
||
|
def get_digits(num: int) -> str:
|
||
|
"""
|
||
|
Computes the sorted sequence of digits of the cube of num.
|
||
|
|
||
|
>>> get_digits(3)
|
||
|
'27'
|
||
|
>>> get_digits(99)
|
||
|
'027999'
|
||
|
>>> get_digits(123)
|
||
|
'0166788'
|
||
|
"""
|
||
|
return "".join(sorted(list(str(num ** 3))))
|
||
|
|
||
|
|
||
|
if __name__ == "__main__":
|
||
|
print(f"{solution() = }")
|