Python/sorts/insertion_sort.py

"""
A pure Python implementation of the insertion sort algorithm

This algorithm sorts a collection by comparing adjacent elements.
When it finds that order is not respected, it moves the element compared
backward until the order is correct.  It then goes back directly to the
element's initial position resuming forward comparison.

For doctests run following command:
python3 -m doctest -v insertion_sort.py

For manual testing run:
python3 insertion_sort.py
"""


def insertion_sort(collection: list) -> list:
    """A pure Python implementation of the insertion sort algorithm

    :param collection: some mutable ordered collection with heterogeneous
    comparable items inside
    :return: the same collection ordered by ascending

    Examples:
    >>> insertion_sort([0, 5, 3, 2, 2])
    [0, 2, 2, 3, 5]
    >>> insertion_sort([]) == sorted([])
    True
    >>> insertion_sort([-2, -5, -45]) == sorted([-2, -5, -45])
    True
    >>> insertion_sort(['d', 'a', 'b', 'e', 'c']) == sorted(['d', 'a', 'b', 'e', 'c'])
    True
    >>> import random
    >>> collection = random.sample(range(-50, 50), 100)
    >>> insertion_sort(collection) == sorted(collection)
    True
    >>> import string
    >>> collection = random.choices(string.ascii_letters + string.digits, k=100)
    >>> insertion_sort(collection) == sorted(collection)
    True
    """

    for insert_index, insert_value in enumerate(collection[1:]):
        temp_index = insert_index
        while insert_index >= 0 and insert_value < collection[insert_index]:
            collection[insert_index + 1] = collection[insert_index]
            insert_index -= 1
        if insert_index != temp_index:
            collection[insert_index + 1] = insert_value
    return collection


if __name__ == "__main__":
    from doctest import testmod

    testmod()

    user_input = input("Enter numbers separated by a comma:\n").strip()
    unsorted = [int(item) for item in user_input.split(",")]
    print(f"{insertion_sort(unsorted) = }")