2019-07-16 23:09:53 +00:00
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"""
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2018-10-19 12:48:28 +00:00
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Problem:
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2019-07-16 23:09:53 +00:00
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A palindromic number reads the same both ways. The largest palindrome made from
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the product of two 2-digit numbers is 9009 = 91 x 99.
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Find the largest palindrome made from the product of two 3-digit numbers which
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is less than N.
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"""
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2019-10-05 05:14:13 +00:00
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2019-07-16 23:09:53 +00:00
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def solution(n):
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"""Returns the largest palindrome made from the product of two 3-digit
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numbers which is less than n.
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2019-08-19 13:37:49 +00:00
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2019-07-16 23:09:53 +00:00
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>>> solution(20000)
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19591
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>>> solution(30000)
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29992
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>>> solution(40000)
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39893
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"""
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2020-01-18 12:24:33 +00:00
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# fetches the next number
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2019-07-16 23:09:53 +00:00
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for number in range(n - 1, 10000, -1):
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2018-10-19 12:48:28 +00:00
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2019-07-16 23:09:53 +00:00
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# converts number into string.
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strNumber = str(number)
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2018-10-19 12:48:28 +00:00
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2019-07-16 23:09:53 +00:00
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# checks whether 'strNumber' is a palindrome.
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if strNumber == strNumber[::-1]:
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2018-10-19 12:48:28 +00:00
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2019-07-16 23:09:53 +00:00
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divisor = 999
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2018-10-19 12:48:28 +00:00
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2019-07-16 23:09:53 +00:00
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# if 'number' is a product of two 3-digit numbers
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# then number is the answer otherwise fetch next number.
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while divisor != 99:
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2019-10-05 05:14:13 +00:00
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if (number % divisor == 0) and (len(str(int(number / divisor))) == 3):
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2019-07-16 23:09:53 +00:00
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return number
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divisor -= 1
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2018-10-19 12:48:28 +00:00
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2019-07-16 23:09:53 +00:00
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if __name__ == "__main__":
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2019-08-19 13:37:49 +00:00
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print(solution(int(input().strip())))
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