mirror of
https://github.com/TheAlgorithms/Python.git
synced 2024-12-18 01:00:15 +00:00
56 lines
1.5 KiB
Python
56 lines
1.5 KiB
Python
|
"""
|
||
|
Author : Alexander Pantyukhin
|
||
|
Date : October 14, 2022
|
||
|
This is implementation Dynamic Programming up bottom approach
|
||
|
to find edit distance.
|
||
|
The aim is to demonstate up bottom approach for solving the task.
|
||
|
The implementation was tested on the
|
||
|
leetcode: https://leetcode.com/problems/edit-distance/
|
||
|
"""
|
||
|
|
||
|
"""
|
||
|
Levinstein distance
|
||
|
Dynamic Programming: up -> down.
|
||
|
"""
|
||
|
|
||
|
|
||
|
def min_distance_up_bottom(word1: str, word2: str) -> int:
|
||
|
"""
|
||
|
>>> min_distance_up_bottom("intention", "execution")
|
||
|
5
|
||
|
>>> min_distance_up_bottom("intention", "")
|
||
|
9
|
||
|
>>> min_distance_up_bottom("", "")
|
||
|
0
|
||
|
>>> min_distance_up_bottom("zooicoarchaeologist", "zoologist")
|
||
|
10
|
||
|
"""
|
||
|
|
||
|
from functools import lru_cache
|
||
|
|
||
|
len_word1 = len(word1)
|
||
|
len_word2 = len(word2)
|
||
|
|
||
|
@lru_cache(maxsize=None)
|
||
|
def min_distance(index1: int, index2: int) -> int:
|
||
|
# if first word index is overflow - delete all from the second word
|
||
|
if index1 >= len_word1:
|
||
|
return len_word2 - index2
|
||
|
# if second word index is overflow - delete all from the first word
|
||
|
if index2 >= len_word2:
|
||
|
return len_word1 - index1
|
||
|
diff = int(word1[index1] != word2[index2]) # current letters not identical
|
||
|
return min(
|
||
|
1 + min_distance(index1 + 1, index2),
|
||
|
1 + min_distance(index1, index2 + 1),
|
||
|
diff + min_distance(index1 + 1, index2 + 1),
|
||
|
)
|
||
|
|
||
|
return min_distance(0, 0)
|
||
|
|
||
|
|
||
|
if __name__ == "__main__":
|
||
|
import doctest
|
||
|
|
||
|
doctest.testmod()
|