2019-08-13 13:51:06 +00:00
|
|
|
|
"""
|
|
|
|
|
Given a partially filled 9×9 2D array, the objective is to fill a 9×9
|
|
|
|
|
square grid with digits numbered 1 to 9, so that every row, column, and
|
|
|
|
|
and each of the nine 3×3 sub-grids contains all of the digits.
|
|
|
|
|
|
|
|
|
|
This can be solved using Backtracking and is similar to n-queens.
|
|
|
|
|
We check to see if a cell is safe or not and recursively call the
|
|
|
|
|
function on the next column to see if it returns True. if yes, we
|
|
|
|
|
have solved the puzzle. else, we backtrack and place another number
|
|
|
|
|
in that cell and repeat this process.
|
|
|
|
|
"""
|
|
|
|
|
# assigning initial values to the grid
|
|
|
|
|
initial_grid = [
|
|
|
|
|
[3, 0, 6, 5, 0, 8, 4, 0, 0],
|
|
|
|
|
[5, 2, 0, 0, 0, 0, 0, 0, 0],
|
|
|
|
|
[0, 8, 7, 0, 0, 0, 0, 3, 1],
|
|
|
|
|
[0, 0, 3, 0, 1, 0, 0, 8, 0],
|
|
|
|
|
[9, 0, 0, 8, 6, 3, 0, 0, 5],
|
|
|
|
|
[0, 5, 0, 0, 9, 0, 6, 0, 0],
|
|
|
|
|
[1, 3, 0, 0, 0, 0, 2, 5, 0],
|
|
|
|
|
[0, 0, 0, 0, 0, 0, 0, 7, 4],
|
|
|
|
|
[0, 0, 5, 2, 0, 6, 3, 0, 0],
|
|
|
|
|
]
|
2019-12-08 21:42:17 +00:00
|
|
|
|
|
2019-08-13 13:51:06 +00:00
|
|
|
|
# a grid with no solution
|
|
|
|
|
no_solution = [
|
|
|
|
|
[5, 0, 6, 5, 0, 8, 4, 0, 3],
|
|
|
|
|
[5, 2, 0, 0, 0, 0, 0, 0, 2],
|
|
|
|
|
[1, 8, 7, 0, 0, 0, 0, 3, 1],
|
|
|
|
|
[0, 0, 3, 0, 1, 0, 0, 8, 0],
|
|
|
|
|
[9, 0, 0, 8, 6, 3, 0, 0, 5],
|
|
|
|
|
[0, 5, 0, 0, 9, 0, 6, 0, 0],
|
|
|
|
|
[1, 3, 0, 0, 0, 0, 2, 5, 0],
|
|
|
|
|
[0, 0, 0, 0, 0, 0, 0, 7, 4],
|
|
|
|
|
[0, 0, 5, 2, 0, 6, 3, 0, 0],
|
|
|
|
|
]
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
def is_safe(grid, row, column, n):
|
|
|
|
|
"""
|
|
|
|
|
This function checks the grid to see if each row,
|
|
|
|
|
column, and the 3x3 subgrids contain the digit 'n'.
|
|
|
|
|
It returns False if it is not 'safe' (a duplicate digit
|
|
|
|
|
is found) else returns True if it is 'safe'
|
|
|
|
|
"""
|
|
|
|
|
for i in range(9):
|
|
|
|
|
if grid[row][i] == n or grid[i][column] == n:
|
|
|
|
|
return False
|
|
|
|
|
|
|
|
|
|
for i in range(3):
|
|
|
|
|
for j in range(3):
|
|
|
|
|
if grid[(row - row % 3) + i][(column - column % 3) + j] == n:
|
|
|
|
|
return False
|
|
|
|
|
|
|
|
|
|
return True
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
def is_completed(grid):
|
|
|
|
|
"""
|
|
|
|
|
This function checks if the puzzle is completed or not.
|
2019-12-08 21:42:17 +00:00
|
|
|
|
it is completed when all the cells are assigned with a non-zero number.
|
|
|
|
|
|
|
|
|
|
>>> is_completed([[0]])
|
|
|
|
|
False
|
|
|
|
|
>>> is_completed([[1]])
|
|
|
|
|
True
|
|
|
|
|
>>> is_completed([[1, 2], [0, 4]])
|
|
|
|
|
False
|
|
|
|
|
>>> is_completed([[1, 2], [3, 4]])
|
|
|
|
|
True
|
|
|
|
|
>>> is_completed(initial_grid)
|
|
|
|
|
False
|
|
|
|
|
>>> is_completed(no_solution)
|
|
|
|
|
False
|
2019-08-13 13:51:06 +00:00
|
|
|
|
"""
|
2019-12-08 21:42:17 +00:00
|
|
|
|
return all(all(cell != 0 for cell in row) for row in grid)
|
2019-08-13 13:51:06 +00:00
|
|
|
|
|
|
|
|
|
|
|
|
|
|
def find_empty_location(grid):
|
|
|
|
|
"""
|
|
|
|
|
This function finds an empty location so that we can assign a number
|
|
|
|
|
for that particular row and column.
|
|
|
|
|
"""
|
|
|
|
|
for i in range(9):
|
|
|
|
|
for j in range(9):
|
|
|
|
|
if grid[i][j] == 0:
|
|
|
|
|
return i, j
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
def sudoku(grid):
|
|
|
|
|
"""
|
|
|
|
|
Takes a partially filled-in grid and attempts to assign values to
|
|
|
|
|
all unassigned locations in such a way to meet the requirements
|
|
|
|
|
for Sudoku solution (non-duplication across rows, columns, and boxes)
|
|
|
|
|
|
|
|
|
|
>>> sudoku(initial_grid) # doctest: +NORMALIZE_WHITESPACE
|
|
|
|
|
[[3, 1, 6, 5, 7, 8, 4, 9, 2],
|
|
|
|
|
[5, 2, 9, 1, 3, 4, 7, 6, 8],
|
|
|
|
|
[4, 8, 7, 6, 2, 9, 5, 3, 1],
|
|
|
|
|
[2, 6, 3, 4, 1, 5, 9, 8, 7],
|
|
|
|
|
[9, 7, 4, 8, 6, 3, 1, 2, 5],
|
|
|
|
|
[8, 5, 1, 7, 9, 2, 6, 4, 3],
|
|
|
|
|
[1, 3, 8, 9, 4, 7, 2, 5, 6],
|
|
|
|
|
[6, 9, 2, 3, 5, 1, 8, 7, 4],
|
|
|
|
|
[7, 4, 5, 2, 8, 6, 3, 1, 9]]
|
|
|
|
|
>>> sudoku(no_solution)
|
|
|
|
|
False
|
|
|
|
|
"""
|
|
|
|
|
|
|
|
|
|
if is_completed(grid):
|
|
|
|
|
return grid
|
|
|
|
|
|
|
|
|
|
row, column = find_empty_location(grid)
|
|
|
|
|
|
|
|
|
|
for digit in range(1, 10):
|
|
|
|
|
if is_safe(grid, row, column, digit):
|
|
|
|
|
grid[row][column] = digit
|
|
|
|
|
|
|
|
|
|
if sudoku(grid):
|
|
|
|
|
return grid
|
|
|
|
|
|
|
|
|
|
grid[row][column] = 0
|
|
|
|
|
|
|
|
|
|
return False
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
def print_solution(grid):
|
|
|
|
|
"""
|
|
|
|
|
A function to print the solution in the form
|
|
|
|
|
of a 9x9 grid
|
|
|
|
|
"""
|
|
|
|
|
for row in grid:
|
|
|
|
|
for cell in row:
|
|
|
|
|
print(cell, end=" ")
|
|
|
|
|
print()
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
if __name__ == "__main__":
|
|
|
|
|
# make a copy of grid so that you can compare with the unmodified grid
|
|
|
|
|
for grid in (initial_grid, no_solution):
|
|
|
|
|
grid = list(map(list, grid))
|
|
|
|
|
solution = sudoku(grid)
|
|
|
|
|
if solution:
|
|
|
|
|
print("grid after solving:")
|
|
|
|
|
print_solution(solution)
|
|
|
|
|
else:
|
|
|
|
|
print("Cannot find a solution.")
|