Python/data_structures/linked_list/singly_LinkedList.py

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2018-10-19 12:48:28 +00:00
from __future__ import print_function
class Node: # create a Node
def __init__(self, data):
self.data = data # given data
self.next = None # given next to None
class Linked_List:
def insert_tail(Head, data):
if Head.next is None:
Head.next = Node(data)
else:
Head.next.insert_tail(data)
def insert_head(Head, data):
tamp = Head
if tamp is None:
newNod = Node() # create a new Node
newNod.data = data
newNod.next = None
Head = newNod # make new node to Head
else:
newNod = Node()
newNod.data = data
newNod.next = Head # put the Head at NewNode Next
Head = newNod # make a NewNode to Head
return Head
def printList(Head): # print every node data
tamp = Head
while tamp is not None:
print(tamp.data)
tamp = tamp.next
def delete_head(Head): # delete from head
if Head is not None:
Head = Head.next
return Head # return new Head
def delete_tail(Head): # delete from tail
if Head is not None:
tamp = Node()
tamp = Head
while tamp.next.next is not None: # find the 2nd last element
tamp = tamp.next
# delete the last element by give next None to 2nd last Element
tamp.next = None
return Head
def isEmpty(Head):
return Head is None # Return if Head is none
def reverse(Head):
prev = None
current = Head
while current:
# Store the current node's next node.
next_node = current.next
# Make the current node's next point backwards
current.next = prev
# Make the previous node be the current node
prev = current
# Make the current node the next node (to progress iteration)
current = next_node
# Return prev in order to put the head at the end
Head = prev
return Head