2023-10-20 21:28:21 +00:00
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"""
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The trifid cipher uses a table to fractionate each plaintext letter into a trigram,
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mixes the constituents of the trigrams, and then applies the table in reverse to turn
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these mixed trigrams into ciphertext letters.
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https://en.wikipedia.org/wiki/Trifid_cipher
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"""
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2021-09-22 21:11:51 +00:00
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from __future__ import annotations
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2019-10-05 05:14:13 +00:00
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2023-10-20 21:28:21 +00:00
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# fmt: off
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TEST_CHARACTER_TO_NUMBER = {
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"A": "111", "B": "112", "C": "113", "D": "121", "E": "122", "F": "123", "G": "131",
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"H": "132", "I": "133", "J": "211", "K": "212", "L": "213", "M": "221", "N": "222",
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"O": "223", "P": "231", "Q": "232", "R": "233", "S": "311", "T": "312", "U": "313",
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"V": "321", "W": "322", "X": "323", "Y": "331", "Z": "332", "+": "333",
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}
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# fmt: off
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2019-04-03 19:27:36 +00:00
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2023-10-20 21:28:21 +00:00
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TEST_NUMBER_TO_CHARACTER = {val: key for key, val in TEST_CHARACTER_TO_NUMBER.items()}
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2019-08-06 10:14:23 +00:00
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2019-04-03 19:27:36 +00:00
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2023-10-20 21:28:21 +00:00
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def __encrypt_part(message_part: str, character_to_number: dict[str, str]) -> str:
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"""
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Arrange the triagram value of each letter of 'message_part' vertically and join
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them horizontally.
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>>> __encrypt_part('ASK', TEST_CHARACTER_TO_NUMBER)
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'132111112'
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"""
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one, two, three = "", "", ""
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for each in (character_to_number[character] for character in message_part):
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2019-04-03 19:27:36 +00:00
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one += each[0]
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two += each[1]
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three += each[2]
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2019-08-06 10:14:23 +00:00
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2019-10-05 05:14:13 +00:00
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return one + two + three
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2019-04-03 19:27:36 +00:00
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2022-10-12 22:54:20 +00:00
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def __decrypt_part(
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message_part: str, character_to_number: dict[str, str]
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2021-04-04 05:22:12 +00:00
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) -> tuple[str, str, str]:
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2023-10-20 21:28:21 +00:00
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"""
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Convert each letter of the input string into their respective trigram values, join
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them and split them into three equal groups of strings which are returned.
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>>> __decrypt_part('ABCDE', TEST_CHARACTER_TO_NUMBER)
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('11111', '21131', '21122')
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"""
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this_part = "".join(character_to_number[character] for character in message_part)
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2019-04-03 19:27:36 +00:00
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result = []
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2023-10-20 21:28:21 +00:00
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tmp = ""
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2022-10-12 22:54:20 +00:00
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for digit in this_part:
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2019-04-03 19:27:36 +00:00
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tmp += digit
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2022-10-12 22:54:20 +00:00
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if len(tmp) == len(message_part):
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2019-04-03 19:27:36 +00:00
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result.append(tmp)
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2019-08-06 10:14:23 +00:00
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tmp = ""
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2019-04-03 19:27:36 +00:00
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return result[0], result[1], result[2]
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2019-10-05 05:14:13 +00:00
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2021-04-04 05:22:12 +00:00
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def __prepare(
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message: str, alphabet: str
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) -> tuple[str, str, dict[str, str], dict[str, str]]:
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2023-10-20 21:28:21 +00:00
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"""
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A helper function that generates the triagrams and assigns each letter of the
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alphabet to its corresponding triagram and stores this in a dictionary
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("character_to_number" and "number_to_character") after confirming if the
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alphabet's length is 27.
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>>> test = __prepare('I aM a BOy','abCdeFghijkLmnopqrStuVwxYZ+')
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>>> expected = ('IAMABOY','ABCDEFGHIJKLMNOPQRSTUVWXYZ+',
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... TEST_CHARACTER_TO_NUMBER, TEST_NUMBER_TO_CHARACTER)
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>>> test == expected
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True
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Testing with incomplete alphabet
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>>> __prepare('I aM a BOy','abCdeFghijkLmnopqrStuVw')
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Traceback (most recent call last):
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...
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KeyError: 'Length of alphabet has to be 27.'
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Testing with extra long alphabets
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>>> __prepare('I aM a BOy','abCdeFghijkLmnopqrStuVwxyzzwwtyyujjgfd')
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Traceback (most recent call last):
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...
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KeyError: 'Length of alphabet has to be 27.'
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Testing with punctuations that are not in the given alphabet
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>>> __prepare('am i a boy?','abCdeFghijkLmnopqrStuVwxYZ+')
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Traceback (most recent call last):
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...
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ValueError: Each message character has to be included in alphabet!
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Testing with numbers
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>>> __prepare(500,'abCdeFghijkLmnopqrStuVwxYZ+')
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Traceback (most recent call last):
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...
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AttributeError: 'int' object has no attribute 'replace'
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"""
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2019-10-05 05:14:13 +00:00
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# Validate message and alphabet, set to upper and remove spaces
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2019-04-03 19:27:36 +00:00
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alphabet = alphabet.replace(" ", "").upper()
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message = message.replace(" ", "").upper()
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2019-10-05 05:14:13 +00:00
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# Check length and characters
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2019-04-03 19:27:36 +00:00
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if len(alphabet) != 27:
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raise KeyError("Length of alphabet has to be 27.")
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2023-10-20 21:28:21 +00:00
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if any(char not in alphabet for char in message):
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raise ValueError("Each message character has to be included in alphabet!")
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2019-04-03 19:27:36 +00:00
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2019-10-05 05:14:13 +00:00
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# Generate dictionares
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2023-10-20 21:28:21 +00:00
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character_to_number = dict(zip(alphabet, TEST_CHARACTER_TO_NUMBER.values()))
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number_to_character = {
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number: letter for letter, number in character_to_number.items()
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}
|
2019-08-06 10:14:23 +00:00
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|
2022-10-12 22:54:20 +00:00
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return message, alphabet, character_to_number, number_to_character
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2019-04-03 19:27:36 +00:00
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|
2019-10-05 05:14:13 +00:00
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|
2022-10-12 22:54:20 +00:00
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def encrypt_message(
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2020-10-16 06:11:52 +00:00
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message: str, alphabet: str = "ABCDEFGHIJKLMNOPQRSTUVWXYZ.", period: int = 5
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) -> str:
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2023-10-20 21:28:21 +00:00
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"""
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encrypt_message
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===============
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Encrypts a message using the trifid_cipher. Any punctuatuions that
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would be used should be added to the alphabet.
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PARAMETERS
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----------
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* message: The message you want to encrypt.
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* alphabet (optional): The characters to be used for the cipher .
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* period (optional): The number of characters you want in a group whilst
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encrypting.
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>>> encrypt_message('I am a boy')
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'BCDGBQY'
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>>> encrypt_message(' ')
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''
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>>> encrypt_message(' aide toi le c iel ta id era ',
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... 'FELIXMARDSTBCGHJKNOPQUVWYZ+',5)
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'FMJFVOISSUFTFPUFEQQC'
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"""
|
2022-10-12 22:54:20 +00:00
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|
message, alphabet, character_to_number, number_to_character = __prepare(
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message, alphabet
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)
|
2019-04-03 19:27:36 +00:00
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|
2023-10-20 21:28:21 +00:00
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encrypted_numeric = ""
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2019-10-05 05:14:13 +00:00
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for i in range(0, len(message) + 1, period):
|
2022-10-12 22:54:20 +00:00
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encrypted_numeric += __encrypt_part(
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message[i : i + period], character_to_number
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)
|
2019-08-06 10:14:23 +00:00
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|
2023-10-20 21:28:21 +00:00
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encrypted = ""
|
2019-04-03 19:27:36 +00:00
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for i in range(0, len(encrypted_numeric), 3):
|
2022-10-12 22:54:20 +00:00
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encrypted += number_to_character[encrypted_numeric[i : i + 3]]
|
2019-04-03 19:27:36 +00:00
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return encrypted
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|
2019-10-05 05:14:13 +00:00
|
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|
2022-10-12 22:54:20 +00:00
|
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def decrypt_message(
|
2020-10-16 06:11:52 +00:00
|
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|
message: str, alphabet: str = "ABCDEFGHIJKLMNOPQRSTUVWXYZ.", period: int = 5
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|
) -> str:
|
2023-10-20 21:28:21 +00:00
|
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|
"""
|
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|
decrypt_message
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|
===============
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|
Decrypts a trifid_cipher encrypted message .
|
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|
PARAMETERS
|
|
|
|
----------
|
|
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|
|
|
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|
* message: The message you want to decrypt .
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|
* alphabet (optional): The characters used for the cipher.
|
|
|
|
* period (optional): The number of characters used in grouping when it
|
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|
was encrypted.
|
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|
|
>>> decrypt_message('BCDGBQY')
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'IAMABOY'
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|
Decrypting with your own alphabet and period
|
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|
>>> decrypt_message('FMJFVOISSUFTFPUFEQQC','FELIXMARDSTBCGHJKNOPQUVWYZ+',5)
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'AIDETOILECIELTAIDERA'
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|
"""
|
2022-10-12 22:54:20 +00:00
|
|
|
message, alphabet, character_to_number, number_to_character = __prepare(
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message, alphabet
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)
|
2019-04-03 19:27:36 +00:00
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|
2023-10-20 21:28:21 +00:00
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decrypted_numeric = []
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for i in range(0, len(message), period):
|
2022-10-12 22:54:20 +00:00
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a, b, c = __decrypt_part(message[i : i + period], character_to_number)
|
2019-08-06 10:14:23 +00:00
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|
2023-08-29 13:18:10 +00:00
|
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for j in range(len(a)):
|
2019-10-05 05:14:13 +00:00
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decrypted_numeric.append(a[j] + b[j] + c[j])
|
2019-04-03 19:27:36 +00:00
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|
2023-10-20 21:28:21 +00:00
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return "".join(number_to_character[each] for each in decrypted_numeric)
|
2019-04-03 19:27:36 +00:00
|
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|
2019-10-05 05:14:13 +00:00
|
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if __name__ == "__main__":
|
2023-10-20 21:28:21 +00:00
|
|
|
import doctest
|
|
|
|
|
|
|
|
doctest.testmod()
|
2019-04-03 19:27:36 +00:00
|
|
|
msg = "DEFEND THE EAST WALL OF THE CASTLE."
|
2022-10-12 22:54:20 +00:00
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|
|
encrypted = encrypt_message(msg, "EPSDUCVWYM.ZLKXNBTFGORIJHAQ")
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|
decrypted = decrypt_message(encrypted, "EPSDUCVWYM.ZLKXNBTFGORIJHAQ")
|
2019-12-07 05:39:59 +00:00
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|
|
print(f"Encrypted: {encrypted}\nDecrypted: {decrypted}")
|