2019-07-16 23:09:53 +00:00
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"""
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n! means n × (n − 1) × ... × 3 × 2 × 1
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For example, 10! = 10 × 9 × ... × 3 × 2 × 1 = 3628800,
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and the sum of the digits in the number 10! is 3 + 6 + 2 + 8 + 8 + 0 + 0 = 27.
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Find the sum of the digits in the number 100!
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"""
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2018-10-19 12:48:28 +00:00
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def factorial(n):
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fact = 1
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2019-07-16 23:09:53 +00:00
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for i in range(1, n + 1):
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2018-10-19 12:48:28 +00:00
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fact *= i
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return fact
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2019-07-16 23:09:53 +00:00
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2018-10-19 12:48:28 +00:00
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def split_and_add(number):
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2019-07-16 23:09:53 +00:00
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"""Split number digits and add them."""
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2018-10-19 12:48:28 +00:00
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sum_of_digits = 0
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2019-07-16 23:09:53 +00:00
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while number > 0:
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2018-10-19 12:48:28 +00:00
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last_digit = number % 10
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sum_of_digits += last_digit
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2019-07-16 23:09:53 +00:00
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number = number // 10 # Removing the last_digit from the given number
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2018-10-19 12:48:28 +00:00
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return sum_of_digits
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2019-07-16 23:09:53 +00:00
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def solution(n):
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"""Returns the sum of the digits in the number 100!
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>>> solution(100)
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648
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>>> solution(50)
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216
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>>> solution(10)
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27
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>>> solution(5)
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3
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>>> solution(3)
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6
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>>> solution(2)
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2
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>>> solution(1)
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1
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"""
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f = factorial(n)
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result = split_and_add(f)
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return result
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2018-10-19 12:48:28 +00:00
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2019-07-16 23:09:53 +00:00
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if __name__ == "__main__":
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print(solution(int(input("Enter the Number: ").strip())))
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