mirror of
https://github.com/TheAlgorithms/Python.git
synced 2024-12-18 09:10:16 +00:00
36 lines
839 B
Python
36 lines
839 B
Python
|
#-.- coding: latin-1 -.-
|
|||
|
from __future__ import print_function
|
|||
|
from math import factorial
|
|||
|
'''
|
|||
|
Combinatoric selections
|
|||
|
Problem 53
|
|||
|
|
|||
|
There are exactly ten ways of selecting three from five, 12345:
|
|||
|
|
|||
|
123, 124, 125, 134, 135, 145, 234, 235, 245, and 345
|
|||
|
|
|||
|
In combinatorics, we use the notation, 5C3 = 10.
|
|||
|
|
|||
|
In general,
|
|||
|
|
|||
|
nCr = n!/(r!(n−r)!),where r ≤ n, n! = n×(n−1)×...×3×2×1, and 0! = 1.
|
|||
|
It is not until n = 23, that a value exceeds one-million: 23C10 = 1144066.
|
|||
|
|
|||
|
How many, not necessarily distinct, values of nCr, for 1 ≤ n ≤ 100, are greater than one-million?
|
|||
|
'''
|
|||
|
try:
|
|||
|
xrange #Python 2
|
|||
|
except NameError:
|
|||
|
xrange = range #Python 3
|
|||
|
|
|||
|
def combinations(n, r):
|
|||
|
return factorial(n)/(factorial(r)*factorial(n-r))
|
|||
|
|
|||
|
total = 0
|
|||
|
|
|||
|
for i in xrange(1, 101):
|
|||
|
for j in xrange(1, i+1):
|
|||
|
if combinations(i, j) > 1e6:
|
|||
|
total += 1
|
|||
|
|
|||
|
print(total)
|