2019-07-16 23:09:53 +00:00
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"""
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2018-10-19 12:48:28 +00:00
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Problem Statement:
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If we list all the natural numbers below 10 that are multiples of 3 or 5,
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2020-10-10 05:33:00 +00:00
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we get 3, 5, 6 and 9. The sum of these multiples is 23.
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2018-10-19 12:48:28 +00:00
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Find the sum of all the multiples of 3 or 5 below N.
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2019-07-16 23:09:53 +00:00
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"""
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2020-10-06 02:42:16 +00:00
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def solution(n: int = 1000) -> int:
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2019-07-16 23:09:53 +00:00
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"""Returns the sum of all the multiples of 3 or 5 below n.
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2019-08-19 13:37:49 +00:00
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2019-07-16 23:09:53 +00:00
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>>> solution(3)
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0
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>>> solution(4)
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3
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>>> solution(10)
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23
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>>> solution(600)
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83700
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"""
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2020-10-10 05:33:00 +00:00
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total = 0
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2019-07-16 23:09:53 +00:00
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terms = (n - 1) // 3
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2020-10-10 05:33:00 +00:00
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total += ((terms) * (6 + (terms - 1) * 3)) // 2 # total of an A.P.
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2019-07-16 23:09:53 +00:00
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terms = (n - 1) // 5
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2020-10-10 05:33:00 +00:00
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total += ((terms) * (10 + (terms - 1) * 5)) // 2
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2019-07-16 23:09:53 +00:00
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terms = (n - 1) // 15
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2020-10-10 05:33:00 +00:00
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total -= ((terms) * (30 + (terms - 1) * 15)) // 2
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return total
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2019-07-16 23:09:53 +00:00
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if __name__ == "__main__":
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2019-08-19 13:37:49 +00:00
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print(solution(int(input().strip())))
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