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20 lines
776 B
Python
20 lines
776 B
Python
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'''
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Problem:
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The sum of the squares of the first ten natural numbers is,
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1^2 + 2^2 + ... + 10^2 = 385
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The square of the sum of the first ten natural numbers is,
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(1 + 2 + ... + 10)^2 = 552 = 3025
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Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.
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Find the difference between the sum of the squares of the first N natural numbers and the square of the sum.
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'''
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from __future__ import print_function
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import math
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def problem6(number=100):
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sum_of_squares = sum([i*i for i in range(1,number+1)])
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square_of_sum = int(math.pow(sum(range(1,number+1)),2))
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return square_of_sum - sum_of_squares
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def main():
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print(problem6())
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if __name__ == '__main__':
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main()
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