Python/ArithmeticAnalysis/NewtonMethod.py

def newton(function,function1,startingInt): #function is the f(x) and function1 is the f'(x)
  x_n=startingInt
  while True:
      x_n1=x_n-function(x_n)/function1(x_n)
      if abs(x_n-x_n1)<0.00001:
          return x_n1
      x_n=x_n1
      
def f(x):
    return (x**3)-2*x-5

def f1(x):
    return 3*(x**2)-2

print(newton(f,f1,3))
Add files via upload There are three methods that find approximately the roots of a non-linear function 2017-12-17 20:02:36 +00:00			`def newton(function,function1,startingInt): #function is the f(x) and function1 is the f'(x)`
			`x_n=startingInt`
			`while True:`
			`x_n1=x_n-function(x_n)/function1(x_n)`
			`if abs(x_n-x_n1)<0.00001:`
			`return x_n1`
			`x_n=x_n1`

			`def f(x):`
Update NeutonMethod.py Removing requirement of math library to make code faster 2018-01-07 17:08:46 +00:00			`return (x*3)-2x-5`
Add files via upload There are three methods that find approximately the roots of a non-linear function 2017-12-17 20:02:36 +00:00
			`def f1(x):`
Update NeutonMethod.py Removing requirement of math library to make code faster 2018-01-07 17:08:46 +00:00			`return 3(x*2)-2`
Add files via upload There are three methods that find approximately the roots of a non-linear function 2017-12-17 20:02:36 +00:00
Update NeutonMethod.py Removing requirement of math library to make code faster 2018-01-07 17:08:46 +00:00			`print(newton(f,f1,3))`