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29 lines
807 B
Python
29 lines
807 B
Python
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"""
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this algorithm tries to find the pattern from every position of
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the mainString if pattern is found from position i it add it to
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the answer and does the same for position i+1
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Complexity : O(n*m)
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n=length of main string
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m=length of pattern string
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"""
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def naivePatternSearch(mainString,pattern):
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patLen=len(pattern)
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strLen=len(mainString)
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position=[]
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for i in range(strLen-patLen+1):
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match_found=True
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for j in range(patLen):
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if mainString[i+j]!=pattern[j]:
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match_found=False
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break
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if match_found:
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position.append(i)
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return position
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mainString="ABAAABCDBBABCDDEBCABC"
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pattern="ABC"
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position=naivePatternSearch(mainString,pattern)
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print("Pattern found in position ")
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for x in position:
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print(x)
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