Python/data_structures/stacks/stock_span_problem.py

52 lines
1.5 KiB
Python
Raw Normal View History

2018-10-19 12:48:28 +00:00
'''
The stock span problem is a financial problem where we have a series of n daily
2018-10-19 12:48:28 +00:00
price quotes for a stock and we need to calculate span of stock's price for all n days.
The span Si of the stock's price on a given day i is defined as the maximum
number of consecutive days just before the given day, for which the price of the stock
2018-10-19 12:48:28 +00:00
on the current day is less than or equal to its price on the given day.
'''
def calculateSpan(price, S):
n = len(price)
# Create a stack and push index of fist element to it
st = []
st.append(0)
# Span value of first element is always 1
S[0] = 1
# Calculate span values for rest of the elements
for i in range(1, n):
# Pop elements from stack whlie stack is not
# empty and top of stack is smaller than price[i]
while( len(st) > 0 and price[st[0]] <= price[i]):
st.pop()
# If stack becomes empty, then price[i] is greater
# than all elements on left of it, i.e. price[0],
# price[1], ..price[i-1]. Else the price[i] is
# greater than elements after top of stack
S[i] = i+1 if len(st) <= 0 else (i - st[0])
# Push this element to stack
st.append(i)
# A utility function to print elements of array
def printArray(arr, n):
for i in range(0,n):
print(arr[i],end =" ")
# Driver program to test above function
price = [10, 4, 5, 90, 120, 80]
S = [0 for i in range(len(price)+1)]
# Fill the span values in array S[]
calculateSpan(price, S)
# Print the calculated span values
printArray(S, len(price))