mirror of
https://github.com/TheAlgorithms/Python.git
synced 2024-11-24 21:41:08 +00:00
45 lines
1.2 KiB
Python
45 lines
1.2 KiB
Python
|
"""
|
||
|
author: Sanket Kittad
|
||
|
Given a string s, find the longest palindromic subsequence's length in s.
|
||
|
Input: s = "bbbab"
|
||
|
Output: 4
|
||
|
Explanation: One possible longest palindromic subsequence is "bbbb".
|
||
|
Leetcode link: https://leetcode.com/problems/longest-palindromic-subsequence/description/
|
||
|
"""
|
||
|
|
||
|
|
||
|
def longest_palindromic_subsequence(input_string: str) -> int:
|
||
|
"""
|
||
|
This function returns the longest palindromic subsequence in a string
|
||
|
>>> longest_palindromic_subsequence("bbbab")
|
||
|
4
|
||
|
>>> longest_palindromic_subsequence("bbabcbcab")
|
||
|
7
|
||
|
"""
|
||
|
n = len(input_string)
|
||
|
rev = input_string[::-1]
|
||
|
m = len(rev)
|
||
|
dp = [[-1] * (m + 1) for i in range(n + 1)]
|
||
|
for i in range(n + 1):
|
||
|
dp[i][0] = 0
|
||
|
for i in range(m + 1):
|
||
|
dp[0][i] = 0
|
||
|
|
||
|
# create and initialise dp array
|
||
|
for i in range(1, n + 1):
|
||
|
for j in range(1, m + 1):
|
||
|
# If characters at i and j are the same
|
||
|
# include them in the palindromic subsequence
|
||
|
if input_string[i - 1] == rev[j - 1]:
|
||
|
dp[i][j] = 1 + dp[i - 1][j - 1]
|
||
|
else:
|
||
|
dp[i][j] = max(dp[i - 1][j], dp[i][j - 1])
|
||
|
|
||
|
return dp[n][m]
|
||
|
|
||
|
|
||
|
if __name__ == "__main__":
|
||
|
import doctest
|
||
|
|
||
|
doctest.testmod()
|