Python/strings/min_cost_string_conversion.py

'''
Algorithm for calculating the most cost-efficient sequence for converting one string into another.
The only allowed operations are
---Copy character with cost cC
---Replace character with cost cR
---Delete character with cost cD
---Insert character with cost cI
'''
def compute_transform_tables(X, Y, cC, cR, cD, cI):
	X = list(X)
	Y = list(Y)
	m = len(X)
	n = len(Y)

	costs = [[0 for _ in range(n+1)] for _ in range(m+1)]
	ops = [[0 for _ in range(n+1)] for _ in range(m+1)]

	for i in range(1, m+1):
		costs[i][0] = i*cD
		ops[i][0] = 'D%c' % X[i-1]

	for i in range(1, n+1):
		costs[0][i] = i*cI
		ops[0][i] = 'I%c' % Y[i-1]

	for i in range(1, m+1):
		for j in range(1, n+1):
			if X[i-1] == Y[j-1]:
				costs[i][j] = costs[i-1][j-1] + cC
				ops[i][j] = 'C%c' % X[i-1]
			else:
				costs[i][j] = costs[i-1][j-1] + cR
				ops[i][j] = 'R%c' % X[i-1] + str(Y[j-1])

			if costs[i-1][j] + cD < costs[i][j]:
				costs[i][j] = costs[i-1][j] + cD
				ops[i][j] = 'D%c' % X[i-1]

			if costs[i][j-1] + cI < costs[i][j]:
				costs[i][j] = costs[i][j-1] + cI
				ops[i][j] = 'I%c' % Y[j-1]

	return costs, ops

def assemble_transformation(ops, i, j):
	if i == 0 and j == 0:
		seq = []
		return seq
	else:
		if ops[i][j][0] == 'C' or ops[i][j][0] == 'R':
			seq = assemble_transformation(ops, i-1, j-1)
			seq.append(ops[i][j])
			return seq
		elif ops[i][j][0] == 'D':
			seq = assemble_transformation(ops, i-1, j)
			seq.append(ops[i][j])
			return seq
		else:
			seq = assemble_transformation(ops, i, j-1)
			seq.append(ops[i][j])
			return seq

if __name__ == '__main__':
	_, operations = compute_transform_tables('Python', 'Algorithms', -1, 1, 2, 2)

	m = len(operations)
	n = len(operations[0])
	sequence = assemble_transformation(operations, m-1, n-1)

	string = list('Python')
	i = 0
	cost = 0

	with open('min_cost.txt', 'w') as file:
		for op in sequence:
			print(''.join(string))

			if op[0] == 'C':
				file.write('%-16s' % 'Copy %c' % op[1])
				file.write('\t\t\t' + ''.join(string))
				file.write('\r\n')

				cost -= 1
			elif op[0] == 'R':
				string[i] = op[2]

				file.write('%-16s' % ('Replace %c' % op[1] + ' with ' + str(op[2])))
				file.write('\t\t' + ''.join(string))
				file.write('\r\n')

				cost += 1
			elif op[0] == 'D':
				string.pop(i)

				file.write('%-16s' % 'Delete %c' % op[1])
				file.write('\t\t\t' + ''.join(string))
				file.write('\r\n')

				cost += 2
			else:
				string.insert(i, op[1])

				file.write('%-16s' % 'Insert %c' % op[1])
				file.write('\t\t\t' + ''.join(string))
				file.write('\r\n')

				cost += 2

			i += 1

		print(''.join(string))
		print('Cost: ', cost)

		file.write('\r\nMinimum cost: ' + str(cost))