2019-07-16 23:09:53 +00:00
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# -*- coding: utf-8 -*-
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"""
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The Fibonacci sequence is defined by the recurrence relation:
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Fn = Fn−1 + Fn−2, where F1 = 1 and F2 = 1.
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Hence the first 12 terms will be:
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F1 = 1
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F2 = 1
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F3 = 2
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F4 = 3
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F5 = 5
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F6 = 8
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F7 = 13
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F8 = 21
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F9 = 34
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F10 = 55
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F11 = 89
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F12 = 144
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The 12th term, F12, is the first term to contain three digits.
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What is the index of the first term in the Fibonacci sequence to contain 1000
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digits?
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"""
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2018-10-19 12:48:28 +00:00
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2019-10-05 05:14:13 +00:00
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2018-10-19 12:48:28 +00:00
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def fibonacci(n):
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2019-07-16 23:09:53 +00:00
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if n == 1 or type(n) is not int:
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return 0
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elif n == 2:
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return 1
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else:
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sequence = [0, 1]
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2019-08-19 13:37:49 +00:00
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for i in range(2, n + 1):
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2019-07-16 23:09:53 +00:00
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sequence.append(sequence[i - 1] + sequence[i - 2])
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return sequence[n]
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2018-10-19 12:48:28 +00:00
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def fibonacci_digits_index(n):
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2019-07-16 23:09:53 +00:00
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digits = 0
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index = 2
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while digits < n:
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index += 1
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digits = len(str(fibonacci(index)))
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return index
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def solution(n):
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"""Returns the index of the first term in the Fibonacci sequence to contain
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n digits.
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2018-10-19 12:48:28 +00:00
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2019-07-16 23:09:53 +00:00
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>>> solution(1000)
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4782
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>>> solution(100)
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476
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>>> solution(50)
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237
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>>> solution(3)
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12
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"""
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return fibonacci_digits_index(n)
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2018-10-19 12:48:28 +00:00
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2019-07-16 23:09:53 +00:00
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if __name__ == "__main__":
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print(solution(int(str(input()).strip())))
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