Python/Maths/3n+1.py

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Python
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2018-10-28 21:23:19 +00:00
def n31(a):# a = initial number
c = 0
l = [a]
while a != 1:
if a % 2 == 0:#if even divide it by 2
a = a // 2
elif a % 2 == 1:#if odd 3n+1
a = 3*a +1
c += 1#counter
l += [a]
print(a)#optional print
print("It took {0} steps.".format(c))#optional finish
return l , c
print(n31(43))