2019-07-16 23:09:53 +00:00
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"""
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2018-12-05 13:25:46 +00:00
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Problem Statement:
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If we list all the natural numbers below 10 that are multiples of 3 or 5,
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2020-10-10 05:33:00 +00:00
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we get 3, 5, 6 and 9. The sum of these multiples is 23.
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2018-12-05 13:25:46 +00:00
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Find the sum of all the multiples of 3 or 5 below N.
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2019-07-16 23:09:53 +00:00
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"""
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2018-12-05 13:25:46 +00:00
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2019-07-16 23:09:53 +00:00
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2020-10-06 02:42:16 +00:00
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def solution(n: int = 1000) -> int:
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2019-07-16 23:09:53 +00:00
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"""Returns the sum of all the multiples of 3 or 5 below n.
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2020-10-10 05:33:00 +00:00
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A straightforward pythonic solution using list comprehension.
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2019-08-19 13:37:49 +00:00
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2019-07-16 23:09:53 +00:00
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>>> solution(3)
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0
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>>> solution(4)
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3
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>>> solution(10)
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23
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>>> solution(600)
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83700
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"""
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return sum([i for i in range(n) if i % 3 == 0 or i % 5 == 0])
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if __name__ == "__main__":
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2019-08-19 13:37:49 +00:00
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print(solution(int(input().strip())))
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