Added an algorithm to the strings sub folder which finds the smallest substring of a given string which contains all of the characters in another given string.

This commit is contained in:
Wilson Strasilla 2024-10-17 13:03:14 -07:00
parent 03a42510b0
commit 00b17c4c7c

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def min_window(search_str: str, target_letters: str) -> str:
"""
Given a string to search, and another string of target char_dict,
return the smallest substring of the search string that contains
all target char_dict.
>>> is_contains_unique_chars("Hello World", "lWl")
"llo W"
>>> is_contains_unique_chars("Hello World", "f")
""
This solution uses a sliding window, alternating between shifting
the end of the window right until all target char_dict are contained
in the window, and shifting the start of the window right until the
window no longer contains every target character.
Time complexity: O(target_count + search_len) ->
The algorithm checks a dictionary at most twice for each character
in search_str.
Space complexity: O(search_len) ->
The primary contributer to additional space is the building of a
dictionary using the search string.
"""
target_count = len(target_letters)
search_len = len(search_str)
#Return if not possible due to string lengths.
if (search_len < target_count):
return ""
#Build dictionary with counts for each letter in target_letters
char_dict = {}
for ch in target_letters:
if ch not in char_dict:
char_dict[ch] = 1
else:
char_dict[ch] += 1
#Initialize window
window_start = 0
window_end = 0
exists = False
min_window_len = search_len + 1
#Start sliding window algorithm
while(window_end < search_len):
#Slide window end right until all search characters are contained
while(target_count > 0 and window_end < search_len):
cur = search_str[window_end]
if cur in char_dict:
char_dict[cur] -= 1
if (char_dict[cur] >= 0):
target_count -= 1
window_end += 1
temp = window_end - window_start
#Check if window is the smallest found so far
if (target_count == 0 and temp < min_window_len):
min_window = [window_start,window_end]
exists = True
min_window_len = temp
#Slide window start right until a search character exits the window
while(target_count == 0 and window_start < window_end):
cur = search_str[window_start]
window_start += 1
if cur in char_dict:
char_dict[cur] += 1
if (char_dict[cur] > 0):
break
temp = window_end - window_start + 1
#Check if window is the smallest found so far
if (temp < min_window_len and target_count == 0):
min_window = [window_start-1,window_end]
min_window_len = temp
target_count = 1
if (exists):
return search_str[min_window[0]:min_window[1]]
else:
return ""