mathdatech/Python
1
0
Fork 0
mirror of https://github.com/TheAlgorithms/Python.git synced 2025-01-19 00:37:02 +00:00
Code Issues Packages Projects Releases Wiki Activity

[pre-commit.ci] auto fixes from pre-commit.com hooks

Browse Source 
for more information, see https://pre-commit.ci
This commit is contained in:
pre-commit-ci[bot] 2024-10-18 17:26:05 +00:00
parent 208b741003
commit 1d034b7243
1 changed files with 16 additions and 14 deletions
Show Stats Download Patch File Download Diff File Expand all files Collapse all files

16
recursions/recursive_digit_sum.py
View File

@ -7,10 +7,10 @@ If has only 1 digit, then its super digit is x .
Otherwise, the super digit of x is equal to the super digit of the sum of the digits of .
For example, the super digit 9875 of will be calculated as:
super_digit(9875) 9+8+7+5 = 29
super_digit(29) 2 + 9 = 11
super_digit(11) 1 + 1 = 2
super_digit(2) = 2
super_digit(9875) 9+8+7+5 = 29
super_digit(29) 2 + 9 = 11
super_digit(11) 1 + 1 = 2
super_digit(2) = 2
ex -2:
@ -24,8 +24,7 @@ super_digit(P) = super_digit(148148148)
= super_digit(1+2)
= super_digit(3)
= 3
"""
"""
"""
@ -37,6 +36,8 @@ Sample Output 0
3
"""
def superDigit(n, k):
# Calculate the initial sum of the digits in n
digit_sum = sum(int(digit) for digit in n)
@ -50,7 +51,8 @@ def superDigit(n, k):
return total_sum
if __name__ == '__main__':
if __name__ == "__main__":
first_multiple_input = input().rstrip().split()
n = first_multiple_input[0]