From 3fae059b6186ade9c5a0e47ede8ecfa42b6112c4 Mon Sep 17 00:00:00 2001 From: Thejus-Paul Date: Thu, 9 Nov 2017 06:15:10 +0530 Subject: [PATCH 1/2] Added Question 9 --- Project Euler/README.md | 21 +++++++++++++-------- 1 file changed, 13 insertions(+), 8 deletions(-) diff --git a/Project Euler/README.md b/Project Euler/README.md index 072203a41..7d8bd2d8d 100644 --- a/Project Euler/README.md +++ b/Project Euler/README.md @@ -2,8 +2,8 @@ Problems are taken from https://projecteuler.net/. -Project Euler is a series of challenging mathematical/computer programming problems that will require more than just mathematical -insights to solve. Project Euler is ideal for mathematicians who are learning to code. +Project Euler is a series of challenging mathematical/computer programming problems that will require more than just mathematical +insights to solve. Project Euler is ideal for mathematicians who are learning to code. Here the efficiency of your code is also checked. I've tried to provide all the best possible solutions. @@ -18,22 +18,27 @@ PROBLEMS: 1,2,3,5,8,13,21,34,55,89,.. By considering the terms in the Fibonacci sequence whose values do not exceed n, find the sum of the even-valued terms. e.g. for n=10, we have {2,8}, sum is 10. - + 3. The prime factors of 13195 are 5,7,13 and 29. What is the largest prime factor of a given number N? e.g. for 10, largest prime factor = 5. For 17, largest prime factor = 17. 4. A palindromic number reads the same both ways. The largest palindrome made from the product of two 2-digit numbers is 9009 = 91 × 99. Find the largest palindrome made from the product of two 3-digit numbers which is less than N. - -5. 2520 is the smallest number that can be divided by each of the numbers from 1 to 10 without any remainder. + +5. 2520 is the smallest number that can be divided by each of the numbers from 1 to 10 without any remainder. What is the smallest positive number that is evenly divisible(divisible with no remainder) by all of the numbers from 1 to N? - + 6. The sum of the squares of the first ten natural numbers is, 1^2 + 2^2 + ... + 10^2 = 385 The square of the sum of the first ten natural numbers is, (1 + 2 + ... + 10)^2 = 552 = 3025 Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640. - Find the difference between the sum of the squares of the first N natural numbers and the square of the sum. - + Find the difference between the sum of the squares of the first N natural numbers and the square of the sum. + 7. By listing the first six prime numbers: 2, 3, 5, 7, 11, and 13, we can see that the 6th prime is 13. What is the Nth prime number? + +9. A Pythagorean triplet is a set of three natural numbers, a < b < c, for which, + a^2 + b^2 = c^2 + There exists exactly one Pythagorean triplet for which a + b + c = 1000. + Find the product abc. From 0f78cd6a55083c62ceec241b6ec22d3e3d056d7b Mon Sep 17 00:00:00 2001 From: Thejus-Paul Date: Sun, 12 Nov 2017 23:56:18 +0530 Subject: [PATCH 2/2] Project Euler Solution Added --- Project Euler/Problem 14/sol1.py | 20 ++++++++++++++++++++ Project Euler/README.md | 7 +++++++ 2 files changed, 27 insertions(+) create mode 100644 Project Euler/Problem 14/sol1.py diff --git a/Project Euler/Problem 14/sol1.py b/Project Euler/Problem 14/sol1.py new file mode 100644 index 000000000..c5050b561 --- /dev/null +++ b/Project Euler/Problem 14/sol1.py @@ -0,0 +1,20 @@ +largest_number = 0 +pre_counter = 0 + +for input1 in range(750000,1000000): + counter = 1 + number = input1 + + while number > 1: + if number % 2 == 0: + number /=2 + counter += 1 + else: + number = (3*number)+1 + counter += 1 + + if counter > pre_counter: + largest_number = input1 + pre_counter = counter + +print('Largest Number:',largest_number,'->',pre_counter,'digits') diff --git a/Project Euler/README.md b/Project Euler/README.md index 7d8bd2d8d..5d7238e40 100644 --- a/Project Euler/README.md +++ b/Project Euler/README.md @@ -42,3 +42,10 @@ PROBLEMS: a^2 + b^2 = c^2 There exists exactly one Pythagorean triplet for which a + b + c = 1000. Find the product abc. + +14. The following iterative sequence is defined for the set of positive integers: + n → n/2 (n is even) + n → 3n + 1 (n is odd) + Using the rule above and starting with 13, we generate the following sequence: + 13 → 40 → 20 → 10 → 5 → 16 → 8 → 4 → 2 → 1 + Which starting number, under one million, produces the longest chain?