Merge branch 'TheAlgorithms:master' into longArthSub

This commit is contained in:
Tejaswi Tyagi 2024-10-04 20:38:05 +05:30 committed by GitHub
commit 3f534f8a87
No known key found for this signature in database
GPG Key ID: B5690EEEBB952194
2 changed files with 84 additions and 25 deletions

View File

@ -1,36 +1,61 @@
def topological_sort(graph):
def topological_sort(graph: dict[int, list[int]]) -> list[int] | None:
"""
Kahn's Algorithm is used to find Topological ordering of Directed Acyclic Graph
using BFS
Perform topological sorting of a Directed Acyclic Graph (DAG)
using Kahn's Algorithm via Breadth-First Search (BFS).
Topological sorting is a linear ordering of vertices in a graph such that for
every directed edge u v, vertex u comes before vertex v in the ordering.
Parameters:
graph: Adjacency list representing the directed graph where keys are
vertices, and values are lists of adjacent vertices.
Returns:
The topologically sorted order of vertices if the graph is a DAG.
Returns None if the graph contains a cycle.
Example:
>>> graph = {0: [1, 2], 1: [3], 2: [3], 3: [4, 5], 4: [], 5: []}
>>> topological_sort(graph)
[0, 1, 2, 3, 4, 5]
>>> graph_with_cycle = {0: [1], 1: [2], 2: [0]}
>>> topological_sort(graph_with_cycle)
"""
indegree = [0] * len(graph)
queue = []
topo = []
cnt = 0
topo_order = []
processed_vertices_count = 0
# Calculate the indegree of each vertex
for values in graph.values():
for i in values:
indegree[i] += 1
# Add all vertices with 0 indegree to the queue
for i in range(len(indegree)):
if indegree[i] == 0:
queue.append(i)
# Perform BFS
while queue:
vertex = queue.pop(0)
cnt += 1
topo.append(vertex)
for x in graph[vertex]:
indegree[x] -= 1
if indegree[x] == 0:
queue.append(x)
processed_vertices_count += 1
topo_order.append(vertex)
if cnt != len(graph):
print("Cycle exists")
else:
print(topo)
# Traverse neighbors
for neighbor in graph[vertex]:
indegree[neighbor] -= 1
if indegree[neighbor] == 0:
queue.append(neighbor)
if processed_vertices_count != len(graph):
return None # no topological ordering exists due to cycle
return topo_order # valid topological ordering
# Adjacency List of Graph
graph = {0: [1, 2], 1: [3], 2: [3], 3: [4, 5], 4: [], 5: []}
topological_sort(graph)
if __name__ == "__main__":
import doctest
doctest.testmod()

View File

@ -17,11 +17,27 @@ def compute_transform_tables(
delete_cost: int,
insert_cost: int,
) -> tuple[list[list[int]], list[list[str]]]:
"""
Finds the most cost efficient sequence
for converting one string into another.
>>> costs, operations = compute_transform_tables("cat", "cut", 1, 2, 3, 3)
>>> costs[0][:4]
[0, 3, 6, 9]
>>> costs[2][:4]
[6, 4, 3, 6]
>>> operations[0][:4]
['0', 'Ic', 'Iu', 'It']
>>> operations[3][:4]
['Dt', 'Dt', 'Rtu', 'Ct']
>>> compute_transform_tables("", "", 1, 2, 3, 3)
([[0]], [['0']])
"""
source_seq = list(source_string)
destination_seq = list(destination_string)
len_source_seq = len(source_seq)
len_destination_seq = len(destination_seq)
costs = [
[0 for _ in range(len_destination_seq + 1)] for _ in range(len_source_seq + 1)
]
@ -31,33 +47,51 @@ def compute_transform_tables(
for i in range(1, len_source_seq + 1):
costs[i][0] = i * delete_cost
ops[i][0] = f"D{source_seq[i - 1]:c}"
ops[i][0] = f"D{source_seq[i - 1]}"
for i in range(1, len_destination_seq + 1):
costs[0][i] = i * insert_cost
ops[0][i] = f"I{destination_seq[i - 1]:c}"
ops[0][i] = f"I{destination_seq[i - 1]}"
for i in range(1, len_source_seq + 1):
for j in range(1, len_destination_seq + 1):
if source_seq[i - 1] == destination_seq[j - 1]:
costs[i][j] = costs[i - 1][j - 1] + copy_cost
ops[i][j] = f"C{source_seq[i - 1]:c}"
ops[i][j] = f"C{source_seq[i - 1]}"
else:
costs[i][j] = costs[i - 1][j - 1] + replace_cost
ops[i][j] = f"R{source_seq[i - 1]:c}" + str(destination_seq[j - 1])
ops[i][j] = f"R{source_seq[i - 1]}" + str(destination_seq[j - 1])
if costs[i - 1][j] + delete_cost < costs[i][j]:
costs[i][j] = costs[i - 1][j] + delete_cost
ops[i][j] = f"D{source_seq[i - 1]:c}"
ops[i][j] = f"D{source_seq[i - 1]}"
if costs[i][j - 1] + insert_cost < costs[i][j]:
costs[i][j] = costs[i][j - 1] + insert_cost
ops[i][j] = f"I{destination_seq[j - 1]:c}"
ops[i][j] = f"I{destination_seq[j - 1]}"
return costs, ops
def assemble_transformation(ops: list[list[str]], i: int, j: int) -> list[str]:
"""
Assembles the transformations based on the ops table.
>>> ops = [['0', 'Ic', 'Iu', 'It'],
... ['Dc', 'Cc', 'Iu', 'It'],
... ['Da', 'Da', 'Rau', 'Rat'],
... ['Dt', 'Dt', 'Rtu', 'Ct']]
>>> x = len(ops) - 1
>>> y = len(ops[0]) - 1
>>> assemble_transformation(ops, x, y)
['Cc', 'Rau', 'Ct']
>>> ops1 = [['0']]
>>> x1 = len(ops1) - 1
>>> y1 = len(ops1[0]) - 1
>>> assemble_transformation(ops1, x1, y1)
[]
"""
if i == 0 and j == 0:
return []
elif ops[i][j][0] in {"C", "R"}: