[pre-commit.ci] auto fixes from pre-commit.com hooks

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data_structures/arrays/array_leader.py

@@ -5,6 +5,7 @@ Given an array arr[] of size n, the task is to find all the Leaders in the array
 Note: The rightmost element is always a leader.
 """
 
+
 def array_leader(arr):
     leaders = []
     for i in range(len(arr)):

data_structures/arrays/max_product_subarray.py

@@ -5,6 +5,7 @@ Output: 60
 Explanation: The subarray with maximum product is {60}.
 """
 
+
 def max_product(arr):
     result = 0
 
@@ -15,5 +16,6 @@ def max_product(arr):
             result = max(result, current_product)
     return result
 
+
 # Test the function with the provided input
 print(max_product([-1, -3, -10, 0, 60]))  # Expected output: 60

data_structures/arrays/max_subarray.py

@@ -12,6 +12,7 @@ Output: 25
 Explanation: The subarray {5, 4, 1, 7, 8} has the largest sum 25.
 """
 
+
 def max_subarray(arr):
     result = arr[0]
 
@@ -22,6 +23,7 @@ def max_subarray(arr):
             result = max(result, current_sum)
     return result
 
+
 # Test the function with the provided inputs
 print(max_subarray([2, 3, -8, 7, -1, 2, 3]))  # Expected output: 11
 print(max_subarray([-2, -4]))  # Expected output: -2

data_structures/arrays/missing_number.py

@@ -1,4 +1,4 @@
-'''
+"""
 Given an array arr[] of size n-1 with integers in the range of [1, n], the task is to find the missing number from the first N integers.
 
 Note: There are no duplicates in the list.
@@ -10,7 +10,8 @@ Explanation: Here the size of the array is 8, so the range will be [1, 8]. The m
 Input: arr[] = {1, 2, 3, 5}, n = 5
 Output: 4
 Explanation: Here the size of the array is 4, so the range will be [1, 5]. The missing number between 1 to 5 is 4
-'''
+"""
+
 
 def find_missing_number(arr, n):
     hash = [0] * (n + 1)
@@ -22,4 +23,5 @@ def find_missing_number(arr, n):
             return i
     return -1
 
+
 print(find_missing_number([1, 2, 3, 4, 6, 7, 8], 8))

data_structures/arrays/rotate_elements.py

@@ -9,11 +9,13 @@ Explanation:
 After 1st rotation – {9, 1, 3, 5, 7}After 2nd rotation – {7, 9, 1, 3, 5}
 """
 
+
 def right_rotate(arr, k):
     n = len(arr)
     k = k % n
     arr = arr[n - k :] + arr[: n - k]
     return arr
 
+
 # Test the function with the provided input
 print(right_rotate([1, 3, 5, 7, 9], 2))  # Expected output: [7, 9, 1, 3, 5]