From 456893cb5f34454e003378a1590b318df33ccfa2 Mon Sep 17 00:00:00 2001 From: Kushagra Bansal Date: Thu, 20 Aug 2020 20:32:14 +0530 Subject: [PATCH] Created problem_43 in project_euler (#2340) * Create __init__.py * Add files via upload * Update sol1.py * Lose a list() Co-authored-by: Christian Clauss --- project_euler/problem_43/__init__.py | 1 + project_euler/problem_43/sol1.py | 58 ++++++++++++++++++++++++++++ 2 files changed, 59 insertions(+) create mode 100644 project_euler/problem_43/__init__.py create mode 100644 project_euler/problem_43/sol1.py diff --git a/project_euler/problem_43/__init__.py b/project_euler/problem_43/__init__.py new file mode 100644 index 000000000..792d60054 --- /dev/null +++ b/project_euler/problem_43/__init__.py @@ -0,0 +1 @@ +# diff --git a/project_euler/problem_43/sol1.py b/project_euler/problem_43/sol1.py new file mode 100644 index 000000000..2fc429f9f --- /dev/null +++ b/project_euler/problem_43/sol1.py @@ -0,0 +1,58 @@ +""" +The number, 1406357289, is a 0 to 9 pandigital number because it is made up of +each of the digits 0 to 9 in some order, but it also has a rather interesting +sub-string divisibility property. + +Let d1 be the 1st digit, d2 be the 2nd digit, and so on. In this way, we note +the following: + +d2d3d4=406 is divisible by 2 +d3d4d5=063 is divisible by 3 +d4d5d6=635 is divisible by 5 +d5d6d7=357 is divisible by 7 +d6d7d8=572 is divisible by 11 +d7d8d9=728 is divisible by 13 +d8d9d10=289 is divisible by 17 +Find the sum of all 0 to 9 pandigital numbers with this property. +""" + + +from itertools import permutations + + +def is_substring_divisible(num: tuple) -> bool: + """ + Returns True if the pandigital number passes + all the divisibility tests. + >>> is_substring_divisible((0, 1, 2, 4, 6, 5, 7, 3, 8, 9)) + False + >>> is_substring_divisible((5, 1, 2, 4, 6, 0, 7, 8, 3, 9)) + False + >>> is_substring_divisible((1, 4, 0, 6, 3, 5, 7, 2, 8, 9)) + True + """ + tests = [2, 3, 5, 7, 11, 13, 17] + for i, test in enumerate(tests): + if (num[i + 1] * 100 + num[i + 2] * 10 + num[i + 3]) % test != 0: + return False + return True + + +def compute_sum(n: int = 10) -> int: + """ + Returns the sum of all pandigital numbers which pass the + divisiility tests. + >>> compute_sum(10) + 16695334890 + """ + list_nums = [ + int("".join(map(str, num))) + for num in permutations(range(n)) + if is_substring_divisible(num) + ] + + return sum(list_nums) + + +if __name__ == "__main__": + print(f"{compute_sum(10) = }")