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"""
Author Atharva Date | atharvad931@gmail.com | git/Atharva9621
The Hilbert Curve (also known as the Hilbert Space Filling Curve) is a continuous
fractal space-filling curve and is a variant of the space-filling Peano curves.
Because it is space-filling, its Hausdorff dimension is 2. Precisely, its image
is the unit square, whose dimension is 2 in any definition of dimension. Its
graph is a compact set homeomorphic to the closed unit interval, with Hausdorff
dimension 1.
Credits:
description adapted from
https://en.wikipedia.org/wiki/Hilbert_curve
also see
https://youtu.be/3s7h2MHQtxc?si=_qIusAJFHYfXIOKn
(3b1b - Hilbert's Curve: Is infinite math useful?)
https://dl.acm.org/doi/pdf/10.1145/290200.290219
Requirements (pip):
- matplotlib
"""
import matplotlib.pyplot as plt
def rotate_pnts(
pnts: list[tuple[float, float]], angle: int
) -> list[tuple[float, float]]:
"""
Rotates a list of points by a given angle (in multiples of 90 degrees).
Since the rotation is limited to multiples of 90 degrees (90, 180, 270, 360),
this function simply reorders the list of points accordingly. The rotation in
each quadrant is achieved by adjusting the starting index of the list
and wrapping around.
Parameters:
-----------
pnts : List[Tuple[float, float]]
A list of tuples, where each tuple represents a point (x, y).
angle : int
The angle of rotation, should be a multiple of 90 degrees
(e.g., 90, 180, 270, 360).
Returns:
--------
List[Tuple[float, float]]
A reordered list of points, rotated by the specified angle.
Example:
--------
>>> rotate_pnts([(1, 1), (0, 1), (0, 0), (1, 0)], 90)
[(0, 1), (0, 0), (1, 0), (1, 1)]
"""
start_index = angle // 90 % 4
return pnts[start_index:] + pnts[:start_index]
def hilbert_curve(
center: tuple[float, float], level: int, side: float = 1, angle: int = 90
) -> list[tuple[float, float]]:
"""
Params:
------
center: Tuple[float, float]- The (x, y) center coordinate of the subsection.
level: int- The recursion depth or subdivision level of the Hilbert curve.
side : float, optional
The length of the side of the square region in which the curve is drawn.
angle : int, optional
The initial rotation angle of the curve in degrees.
It should be a multiple of 90 degrees. (default=90)
Returns:
------
pts: List[Tuple[float, float]] -
A list of points (x, y) representing the Hilbert curve for the given level.
Example:
--------
>>> hilbert_curve((0, 0), 1, angle=0)
[(0.25, 0.25), (-0.25, 0.25), (-0.25, -0.25), (0.25, -0.25)]
"""
x, y = center
angle = angle % 360
pnts = [
(x + side / 4, y + side / 4),
(x - side / 4, y + side / 4),
(x - side / 4, y - side / 4),
(x + side / 4, y - side / 4),
]
pnts = rotate_pnts(pnts, angle)
if level == 1:
return pnts
else:
return (
hilbert_curve(pnts[0], level - 1, side / 2, angle=angle + 90)[::-1]
+ hilbert_curve(pnts[1], level - 1, side / 2, angle=angle)
+ hilbert_curve(pnts[2], level - 1, side / 2, angle=angle)
+ hilbert_curve(pnts[3], level - 1, side / 2, angle=angle - 90)[::-1]
)
def plot_hilbert_curve(points: list[tuple[float, float]]) -> None:
"""
Plots the hilbert curve using mtplotlib
Example
--------
>>> plot_hilbert_curve([(-0.25, 0.25), (-0.25, -0.25), (0.25, -0.25), (0.25, 0.25)])
"""
x_coords = [p[0] for p in points]
y_coords = [p[1] for p in points]
plt.plot(x_coords, y_coords, marker="o", linestyle="-")
plt.gca().set_aspect("equal", adjustable="box") # Make the plot square
plt.title("Hilbert Curve")
plt.show()
if __name__ == "__main__":
import doctest
# Run doctests
doctest.testmod()
# Plotting Hilbert Curve
plot_hilbert_curve(hilbert_curve((0, 0), 4))