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Hacktoberfest 2020: Add style improvements for Project Euler Problem 03 (#2917)
* Fix typehints in project_euler/problem01 Squashed commit of the following: commit 6801d073b31bf702814861cd3b07b634ca295bfa Author: Archaengel <god11341258@gmail.com> Date: Mon Oct 5 16:40:10 2020 -0700 Fix typehints in project_euler/problem01 commit 29afc3af114abd1b99dc3f7c8fc99128229db131 Author: Archaengel <god11341258@gmail.com> Date: Mon Oct 5 15:06:34 2020 -0700 Add typehints and default argument for project_euler/problem_01 * Add default args, typehints, and expand variable names for PE prob 02 * Add style improvements for first solution of PE Problem 02 * Add default arg and typehints for second solution of PE Problem 02 * Add default arg for third solution of PE Problem 02 * Add style improvements for 1st soln of PE problem 03 * Add default arg and typehints for 2nd soln of PE problem 03 * Add default arg for 3rd soln of PE problem 03 * Remove unnecessary newlines * Remove unnecessary newlines * Fix end of file for 2nd soln in PE problem 03
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@ -5,24 +5,43 @@ of a given number N?
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e.g. for 10, largest prime factor = 5. For 17, largest prime factor = 17.
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"""
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import math
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def isprime(no):
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if no == 2:
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def isprime(num: int) -> bool:
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"""Returns boolean representing primality of given number num.
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>>> isprime(2)
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True
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>>> isprime(3)
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True
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>>> isprime(27)
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False
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>>> isprime(2999)
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True
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>>> isprime(0)
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Traceback (most recent call last):
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...
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ValueError: Parameter num must be greater or equal to two.
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>>> isprime(1)
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Traceback (most recent call last):
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...
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ValueError: Parameter num must be greater or equal to two.
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"""
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if num <= 1:
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raise ValueError("Parameter num must be greater or equal to two.")
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if num == 2:
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return True
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elif no % 2 == 0:
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elif num % 2 == 0:
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return False
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sq = int(math.sqrt(no)) + 1
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for i in range(3, sq, 2):
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if no % i == 0:
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for i in range(3, int(math.sqrt(num)) + 1, 2):
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if num % i == 0:
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return False
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return True
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def solution(n):
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def solution(n: int = 600851475143) -> int:
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"""Returns the largest prime factor of a given number n.
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>>> solution(13195)
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29
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>>> solution(10)
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@ -54,24 +73,21 @@ def solution(n):
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raise TypeError("Parameter n must be int or passive of cast to int.")
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if n <= 0:
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raise ValueError("Parameter n must be greater or equal to one.")
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maxNumber = 0
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max_number = 0
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if isprime(n):
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return n
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else:
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while n % 2 == 0:
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n = n / 2
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if isprime(n):
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return int(n)
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else:
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n1 = int(math.sqrt(n)) + 1
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for i in range(3, n1, 2):
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if n % i == 0:
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if isprime(n / i):
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maxNumber = n / i
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break
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elif isprime(i):
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maxNumber = i
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return maxNumber
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while n % 2 == 0:
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n //= 2
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if isprime(n):
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return n
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for i in range(3, int(math.sqrt(n)) + 1, 2):
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if n % i == 0:
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if isprime(n / i):
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max_number = n / i
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break
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elif isprime(i):
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max_number = i
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return max_number
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if __name__ == "__main__":
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@ -7,9 +7,8 @@ e.g. for 10, largest prime factor = 5. For 17, largest prime factor = 17.
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"""
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def solution(n):
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def solution(n: int = 600851475143) -> int:
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"""Returns the largest prime factor of a given number n.
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>>> solution(13195)
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29
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>>> solution(10)
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@ -7,9 +7,8 @@ e.g. for 10, largest prime factor = 5. For 17, largest prime factor = 17.
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"""
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def solution(n: int) -> int:
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def solution(n: int = 600851475143) -> int:
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"""Returns the largest prime factor of a given number n.
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>>> solution(13195)
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29
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>>> solution(10)
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@ -52,12 +51,8 @@ def solution(n: int) -> int:
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while n % i == 0:
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n = n / i
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i += 1
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return int(ans)
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if __name__ == "__main__":
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# print(solution(int(input().strip())))
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import doctest
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doctest.testmod()
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print(solution(int(input().strip())))
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