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Enhance readability of Minimax (#10838)
* Enhance readability of Minimax * [pre-commit.ci] auto fixes from pre-commit.com hooks for more information, see https://pre-commit.ci * Reduce line overflow * Update backtracking/minimax.py Co-authored-by: Tianyi Zheng <tianyizheng02@gmail.com> * Update backtracking/minimax.py Co-authored-by: Tianyi Zheng <tianyizheng02@gmail.com> * Update backtracking/minimax.py Co-authored-by: Tianyi Zheng <tianyizheng02@gmail.com> * Remove line overflow --------- Co-authored-by: pre-commit-ci[bot] <66853113+pre-commit-ci[bot]@users.noreply.github.com> Co-authored-by: Tianyi Zheng <tianyizheng02@gmail.com>
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@ -16,6 +16,22 @@ def minimax(
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depth: int, node_index: int, is_max: bool, scores: list[int], height: float
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) -> int:
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"""
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This function implements the minimax algorithm, which helps achieve the optimal
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score for a player in a two-player game by checking all possible moves.
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If the player is the maximizer, then the score is maximized.
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If the player is the minimizer, then the score is minimized.
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Parameters:
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- depth: Current depth in the game tree.
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- node_index: Index of the current node in the scores list.
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- is_max: A boolean indicating whether the current move
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is for the maximizer (True) or minimizer (False).
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- scores: A list containing the scores of the leaves of the game tree.
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- height: The maximum height of the game tree.
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Returns:
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- An integer representing the optimal score for the current player.
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>>> import math
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>>> scores = [90, 23, 6, 33, 21, 65, 123, 34423]
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>>> height = math.log(len(scores), 2)
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@ -37,19 +53,24 @@ def minimax(
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if depth < 0:
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raise ValueError("Depth cannot be less than 0")
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if len(scores) == 0:
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raise ValueError("Scores cannot be empty")
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# Base case: If the current depth equals the height of the tree,
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# return the score of the current node.
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if depth == height:
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return scores[node_index]
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# If it's the maximizer's turn, choose the maximum score
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# between the two possible moves.
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if is_max:
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return max(
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minimax(depth + 1, node_index * 2, False, scores, height),
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minimax(depth + 1, node_index * 2 + 1, False, scores, height),
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)
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# If it's the minimizer's turn, choose the minimum score
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# between the two possible moves.
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return min(
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minimax(depth + 1, node_index * 2, True, scores, height),
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minimax(depth + 1, node_index * 2 + 1, True, scores, height),
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@ -57,8 +78,11 @@ def minimax(
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def main() -> None:
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# Sample scores and height calculation
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scores = [90, 23, 6, 33, 21, 65, 123, 34423]
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height = math.log(len(scores), 2)
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# Calculate and print the optimal value using the minimax algorithm
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print("Optimal value : ", end="")
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print(minimax(0, 0, True, scores, height))
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