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Added doctests to min_cost_string_conversion.py and removed :c specifier (#11721)
* Added doctests to min_cost_string_conversion.py and removed :c specifier * [pre-commit.ci] auto fixes from pre-commit.com hooks for more information, see https://pre-commit.ci * resolved line length issues based on ruff requirements * modified in compliance with ruff for line length * Update strings/min_cost_string_conversion.py --------- Co-authored-by: pre-commit-ci[bot] <66853113+pre-commit-ci[bot]@users.noreply.github.com> Co-authored-by: Tianyi Zheng <tianyizheng02@gmail.com>
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@ -17,6 +17,23 @@ def compute_transform_tables(
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delete_cost: int,
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delete_cost: int,
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insert_cost: int,
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insert_cost: int,
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) -> tuple[list[list[int]], list[list[str]]]:
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) -> tuple[list[list[int]], list[list[str]]]:
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"""
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Finds the most cost efficient sequence
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for converting one string into another.
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>>> costs, operations = compute_transform_tables("cat", "cut", 1, 2, 3, 3)
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>>> costs[0][:4]
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[0, 3, 6, 9]
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>>> costs[2][:4]
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[6, 4, 3, 6]
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>>> operations[0][:4]
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['0', 'Ic', 'Iu', 'It']
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>>> operations[3][:4]
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['Dt', 'Dt', 'Rtu', 'Ct']
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>>> compute_transform_tables("", "", 1, 2, 3, 3)
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([[0]], [['0']])
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"""
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source_seq = list(source_string)
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source_seq = list(source_string)
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destination_seq = list(destination_string)
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destination_seq = list(destination_string)
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len_source_seq = len(source_seq)
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len_source_seq = len(source_seq)
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@ -57,6 +74,24 @@ def compute_transform_tables(
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def assemble_transformation(ops: list[list[str]], i: int, j: int) -> list[str]:
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def assemble_transformation(ops: list[list[str]], i: int, j: int) -> list[str]:
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"""
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Assembles the transformations based on the ops table.
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>>> ops = [['0', 'Ic', 'Iu', 'It'],
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... ['Dc', 'Cc', 'Iu', 'It'],
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... ['Da', 'Da', 'Rau', 'Rat'],
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... ['Dt', 'Dt', 'Rtu', 'Ct']]
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>>> x = len(ops) - 1
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>>> y = len(ops[0]) - 1
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>>> assemble_transformation(ops, x, y)
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['Cc', 'Rau', 'Ct']
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>>> ops1 = [['0']]
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>>> x1 = len(ops1) - 1
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>>> y1 = len(ops1[0]) - 1
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>>> assemble_transformation(ops1, x1, y1)
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[]
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"""
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if i == 0 and j == 0:
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if i == 0 and j == 0:
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return []
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return []
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elif ops[i][j][0] in {"C", "R"}:
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elif ops[i][j][0] in {"C", "R"}:
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