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following recommendations
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@ -1,7 +1,6 @@
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from typing import List, Tuple, Union
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def split_list(timings: List[Union[int, float, str]]) -> Tuple[List[Union[int, float]]]:
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def split_list(timings: List[Union[int, float, str]]) -> Tuple[List[Union[int, float]], List[Union[int, float]], Union[int, float]]:
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"""
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This algorithm is a brute-force search over (nearly) all 2^n
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@ -9,7 +8,7 @@ def split_list(timings: List[Union[int, float, str]]) -> Tuple[List[Union[int, f
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the asymptotic runtime of this code is: O(n * 2^n)
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this is a case of the partition problem.
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it accepts a multiset ( list ) of positive integers,
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it accepts a multiset ( list ) of integers,
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distributes them, and returns a tuple, containing two lists,
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with minimal difference between their sums
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@ -25,7 +24,7 @@ def split_list(timings: List[Union[int, float, str]]) -> Tuple[List[Union[int, f
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([10, 11], [12.5, 9], 0.5)
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>>> split_list(["twelve", "ten", "eleven", "nine"])
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Traceback (most recent call last):
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ValueError: only numbers please
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ValueError: Timings must be a list of numbers
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"""
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@ -42,13 +41,13 @@ def split_list(timings: List[Union[int, float, str]]) -> Tuple[List[Union[int, f
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elif isinstance(current_element, (int, float)):
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timings[i] = abs(current_element)
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else:
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raise ValueError("only numbers please")
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raise ValueError("Timings must be a list of numbers")
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if len(timings) == 0:
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return ([], [], 0)
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elif len(timings) == 1:
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return ([timings[0]], [], 1)
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else:
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return ([timings[0]], [], timings[0])
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result = None
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n = len(timings)
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smallest_diff = float("inf")
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