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Fixed issue #1368 (#1482)

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* Changed as suggested

Now return in same format as oct() returns

* Slight change

* Fixed issue #1368, return values for large number now is fixed and does not return in scientific notation

* Update decimal_to_octal.py
This commit is contained in:
Jawpral 2019-12-09 03:57:42 +05:30 committed by Christian Clauss
parent 43905efe29
commit 74d96ab355
1 changed files with 7 additions and 3 deletions
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10
conversions/decimal_to_octal.py
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@ -6,8 +6,12 @@ import math
# https://github.com/TheAlgorithms/Javascript/blob/master/Conversions/DecimalToOctal.js # https://github.com/TheAlgorithms/Javascript/blob/master/Conversions/DecimalToOctal.js
def decimal_to_octal(num): def decimal_to_octal(num: int) -> str:
"""Convert a Decimal Number to an Octal Number.""" """Convert a Decimal Number to an Octal Number.
>>> all(decimal_to_octal(i) == oct(i) for i in (0, 2, 8, 64, 65, 216, 255, 256, 512))
True
"""
octal = 0 octal = 0
counter = 0 counter = 0
while num > 0: while num > 0:
@ -16,7 +20,7 @@ def decimal_to_octal(num):
counter += 1 counter += 1
num = math.floor(num / 8) # basically /= 8 without remainder if any num = math.floor(num / 8) # basically /= 8 without remainder if any
# This formatting removes trailing '.0' from `octal`. # This formatting removes trailing '.0' from `octal`.
return "{0:g}".format(float(octal)) return f"0o{int(octal)}"
def main(): def main():