Added functionality to calculate the diameter of given binary tree (#10526)

* Added code to find diameter of given binary tree

* Modified diameter_of_binary_tree file

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* Update diameter_of_binary_tree.py

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* Update diameter_of_binary_tree.py

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Vinayak Upadhyay 2023-10-16 22:16:44 +05:30 committed by GitHub
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"""
The diameter/width of a tree is defined as the number of nodes on the longest path
between two end nodes.
"""
from __future__ import annotations
from dataclasses import dataclass
@dataclass
class Node:
data: int
left: Node | None = None
right: Node | None = None
def depth(self) -> int:
"""
>>> root = Node(1)
>>> root.depth()
1
>>> root.left = Node(2)
>>> root.depth()
2
>>> root.left.depth()
1
>>> root.right = Node(3)
>>> root.depth()
2
"""
left_depth = self.left.depth() if self.left else 0
right_depth = self.right.depth() if self.right else 0
return max(left_depth, right_depth) + 1
def diameter(self) -> int:
"""
>>> root = Node(1)
>>> root.diameter()
1
>>> root.left = Node(2)
>>> root.diameter()
2
>>> root.left.diameter()
1
>>> root.right = Node(3)
>>> root.diameter()
3
"""
left_depth = self.left.depth() if self.left else 0
right_depth = self.right.depth() if self.right else 0
return left_depth + right_depth + 1
if __name__ == "__main__":
from doctest import testmod
testmod()
root = Node(1)
root.left = Node(2)
root.right = Node(3)
root.left.left = Node(4)
root.left.right = Node(5)
r"""
Constructed binary tree is
1
/ \
2 3
/ \
4 5
"""
print(f"{root.diameter() = }") # 4
print(f"{root.left.diameter() = }") # 3
print(f"{root.right.diameter() = }") # 1