From 9ed60ba882c7b6a07b7b951447558710fcbdcc4b Mon Sep 17 00:00:00 2001
From: Daniel Ingram <ingramds@appstate.edu>
Date: Mon, 2 Apr 2018 12:20:53 -0400
Subject: [PATCH 1/3] Solution to Problem 36

---
 Project Euler/Problem 36/sol1.py | 30 ++++++++++++++++++++++++++++++
 1 file changed, 30 insertions(+)
 create mode 100644 Project Euler/Problem 36/sol1.py

diff --git a/Project Euler/Problem 36/sol1.py b/Project Euler/Problem 36/sol1.py
new file mode 100644
index 000000000..d78e7e59f
--- /dev/null
+++ b/Project Euler/Problem 36/sol1.py	
@@ -0,0 +1,30 @@
+from __future__ import print_function
+'''
+Double-base palindromes
+Problem 36
+The decimal number, 585 = 10010010012 (binary), is palindromic in both bases.
+
+Find the sum of all numbers, less than one million, which are palindromic in base 10 and base 2.
+
+(Please note that the palindromic number, in either base, may not include leading zeros.)
+'''
+try:
+	xrange		#Python 2
+except NameError:
+	xrange = range	#Python 3
+
+def is_palindrome(n):
+	n = str(n)
+
+	if n == n[::-1]:
+		return True
+	else:
+		return False
+
+total = 0
+
+for i in xrange(1, 1000000):
+	if is_palindrome(i) and is_palindrome(bin(i).split('b')[1]):
+		total += i
+
+print(total)
\ No newline at end of file

From 6a8f1cf2325253f7643bd23d1e91cb410b3cbb00 Mon Sep 17 00:00:00 2001
From: Daniel Ingram <ingramds@appstate.edu>
Date: Mon, 2 Apr 2018 23:46:28 -0400
Subject: [PATCH 2/3] Solution to Problem 40

---
 Project Euler/Problem 40/sol1.py | 26 ++++++++++++++++++++++++++
 1 file changed, 26 insertions(+)
 create mode 100644 Project Euler/Problem 40/sol1.py

diff --git a/Project Euler/Problem 40/sol1.py b/Project Euler/Problem 40/sol1.py
new file mode 100644
index 000000000..ab4017512
--- /dev/null
+++ b/Project Euler/Problem 40/sol1.py	
@@ -0,0 +1,26 @@
+#-.- coding: latin-1 -.-
+from __future__ import print_function
+'''
+Champernowne's constant
+Problem 40
+An irrational decimal fraction is created by concatenating the positive integers:
+
+0.123456789101112131415161718192021...
+
+It can be seen that the 12th digit of the fractional part is 1.
+
+If dn represents the nth digit of the fractional part, find the value of the following expression.
+
+d1 × d10 × d100 × d1000 × d10000 × d100000 × d1000000
+'''
+
+constant = []
+i = 1
+
+while len(constant) < 1e6:
+	constant.append(str(i))
+	i += 1
+
+constant = ''.join(constant)
+
+print(int(constant[0])*int(constant[9])*int(constant[99])*int(constant[999])*int(constant[9999])*int(constant[99999])*int(constant[999999]))
\ No newline at end of file

From b172ec38418044cefaaa6aafcf56eee172308de2 Mon Sep 17 00:00:00 2001
From: Daniel Ingram <ingramds@appstate.edu>
Date: Tue, 3 Apr 2018 00:04:38 -0400
Subject: [PATCH 3/3] Solution to Problem 52

---
 Project Euler/Problem 52/sol1.py | 23 +++++++++++++++++++++++
 1 file changed, 23 insertions(+)
 create mode 100644 Project Euler/Problem 52/sol1.py

diff --git a/Project Euler/Problem 52/sol1.py b/Project Euler/Problem 52/sol1.py
new file mode 100644
index 000000000..376b4cfa1
--- /dev/null
+++ b/Project Euler/Problem 52/sol1.py	
@@ -0,0 +1,23 @@
+from __future__ import print_function
+'''
+Permuted multiples
+Problem 52
+
+It can be seen that the number, 125874, and its double, 251748, contain exactly the same digits, but in a different order.
+
+Find the smallest positive integer, x, such that 2x, 3x, 4x, 5x, and 6x, contain the same digits.
+'''
+i = 1
+
+while True:
+	if sorted(list(str(i))) == \
+       sorted(list(str(2*i))) == \
+       sorted(list(str(3*i))) == \
+       sorted(list(str(4*i))) == \
+       sorted(list(str(5*i))) == \
+       sorted(list(str(6*i))):
+		break
+
+	i += 1
+
+print(i) 
\ No newline at end of file