mirror of
https://github.com/TheAlgorithms/Python.git
synced 2024-11-27 15:01:08 +00:00
matrix/count_paths.py (#7533)
* added recursive dfs backtracking for count paths with doctests * fixed doc testing * added type hints * redefined r as row, c as col * fixed naming conventions, ran mypy, only tests that didn't pass were using List[], rathan list() * added another doctest, as well as a explanation above * [pre-commit.ci] auto fixes from pre-commit.com hooks for more information, see https://pre-commit.ci * Update matrix/count_paths.py Co-authored-by: Chris O <46587501+ChrisO345@users.noreply.github.com> * Update matrix/count_paths.py Co-authored-by: Chris O <46587501+ChrisO345@users.noreply.github.com> * [pre-commit.ci] auto fixes from pre-commit.com hooks for more information, see https://pre-commit.ci * Apply suggestions from code review Co-authored-by: Caeden Perelli-Harris <caedenperelliharris@gmail.com> Co-authored-by: J <jasondevers@wireless-10-105-49-243.umd.edu> Co-authored-by: pre-commit-ci[bot] <66853113+pre-commit-ci[bot]@users.noreply.github.com> Co-authored-by: Chris O <46587501+ChrisO345@users.noreply.github.com> Co-authored-by: Caeden Perelli-Harris <caedenperelliharris@gmail.com>
This commit is contained in:
parent
3ec0aa85c0
commit
7b7b3dd086
75
matrix/count_paths.py
Normal file
75
matrix/count_paths.py
Normal file
|
@ -0,0 +1,75 @@
|
||||||
|
"""
|
||||||
|
Given a grid, where you start from the top left position [0, 0],
|
||||||
|
you want to find how many paths you can take to get to the bottom right position.
|
||||||
|
|
||||||
|
start here -> 0 0 0 0
|
||||||
|
1 1 0 0
|
||||||
|
0 0 0 1
|
||||||
|
0 1 0 0 <- finish here
|
||||||
|
how many 'distinct' paths can you take to get to the finish?
|
||||||
|
Using a recursive depth-first search algorithm below, you are able to
|
||||||
|
find the number of distinct unique paths (count).
|
||||||
|
|
||||||
|
'*' will demonstrate a path
|
||||||
|
In the example above, there are two distinct paths:
|
||||||
|
1. 2.
|
||||||
|
* * * 0 * * * *
|
||||||
|
1 1 * 0 1 1 * *
|
||||||
|
0 0 * 1 0 0 * 1
|
||||||
|
0 1 * * 0 1 * *
|
||||||
|
"""
|
||||||
|
|
||||||
|
|
||||||
|
def depth_first_search(grid: list[list[int]], row: int, col: int, visit: set) -> int:
|
||||||
|
"""
|
||||||
|
Recursive Backtracking Depth First Search Algorithm
|
||||||
|
|
||||||
|
Starting from top left of a matrix, count the number of
|
||||||
|
paths that can reach the bottom right of a matrix.
|
||||||
|
1 represents a block (inaccessible)
|
||||||
|
0 represents a valid space (accessible)
|
||||||
|
|
||||||
|
0 0 0 0
|
||||||
|
1 1 0 0
|
||||||
|
0 0 0 1
|
||||||
|
0 1 0 0
|
||||||
|
>>> grid = [[0, 0, 0, 0], [1, 1, 0, 0], [0, 0, 0, 1], [0, 1, 0, 0]]
|
||||||
|
>>> depth_first_search(grid, 0, 0, set())
|
||||||
|
2
|
||||||
|
|
||||||
|
0 0 0 0 0
|
||||||
|
0 1 1 1 0
|
||||||
|
0 1 1 1 0
|
||||||
|
0 0 0 0 0
|
||||||
|
>>> grid = [[0, 0, 0, 0, 0], [0, 1, 1, 1, 0], [0, 1, 1, 1, 0], [0, 0, 0, 0, 0]]
|
||||||
|
>>> depth_first_search(grid, 0, 0, set())
|
||||||
|
2
|
||||||
|
"""
|
||||||
|
row_length, col_length = len(grid), len(grid[0])
|
||||||
|
if (
|
||||||
|
min(row, col) < 0
|
||||||
|
or row == row_length
|
||||||
|
or col == col_length
|
||||||
|
or (row, col) in visit
|
||||||
|
or grid[row][col] == 1
|
||||||
|
):
|
||||||
|
return 0
|
||||||
|
if row == row_length - 1 and col == col_length - 1:
|
||||||
|
return 1
|
||||||
|
|
||||||
|
visit.add((row, col))
|
||||||
|
|
||||||
|
count = 0
|
||||||
|
count += depth_first_search(grid, row + 1, col, visit)
|
||||||
|
count += depth_first_search(grid, row - 1, col, visit)
|
||||||
|
count += depth_first_search(grid, row, col + 1, visit)
|
||||||
|
count += depth_first_search(grid, row, col - 1, visit)
|
||||||
|
|
||||||
|
visit.remove((row, col))
|
||||||
|
return count
|
||||||
|
|
||||||
|
|
||||||
|
if __name__ == "__main__":
|
||||||
|
import doctest
|
||||||
|
|
||||||
|
doctest.testmod()
|
Loading…
Reference in New Issue
Block a user