mirror of
https://github.com/TheAlgorithms/Python.git
synced 2024-11-24 05:21:09 +00:00
commit
7bb26e9b2a
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@ -5,8 +5,8 @@ we get 3,5,6 and 9. The sum of these multiples is 23.
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Find the sum of all the multiples of 3 or 5 below N.
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'''
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n = int(raw_input().strip())
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sum=0;
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sum=0
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for a in range(3,n):
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if(a%3==0 or a%5==0):
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sum+=a
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print sum;
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print sum
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@ -8,8 +8,8 @@ Find the sum of all the multiples of 3 or 5 below N.
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This solution is based on the pattern that the successive numbers in the series follow: 0+3,+2,+1,+3,+1,+2,+3.
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'''
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n = int(raw_input().strip())
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sum=0;
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num=0;
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sum=0
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num=0
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while(1):
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num+=3
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if(num>=n):
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@ -39,4 +39,4 @@ while(1):
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if(num>=n):
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break
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sum+=num
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print sum;
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print sum
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@ -8,11 +8,13 @@ e.g. for n=10, we have {2,8}, sum is 10.
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'''
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n = int(raw_input().strip())
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i=1; j=2; sum=0
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i=1
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j=2
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sum=0
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while(j<=n):
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if((j&1)==0): #can also use (j%2==0)
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sum+=j
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temp=i
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i=j
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j=temp+i
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print sum
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print sum
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@ -17,7 +17,7 @@ def isprime(no):
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return False
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return True
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max=0
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maxNumber = 0
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n=int(input())
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if(isprime(n)):
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print n
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@ -31,8 +31,8 @@ else:
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for i in range(3,n1,2):
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if(n%i==0):
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if(isprime(n/i)):
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max=n/i
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maxNumber = n/i
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break
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elif(isprime(i)):
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max=i
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print max
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maxNumber = i
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print maxNumber
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34
Project Euler/Problem 29/solution.py
Normal file
34
Project Euler/Problem 29/solution.py
Normal file
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@ -0,0 +1,34 @@
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def main():
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"""
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Consider all integer combinations of ab for 2 <= a <= 5 and 2 <= b <= 5:
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22=4, 23=8, 24=16, 25=32
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32=9, 33=27, 34=81, 35=243
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42=16, 43=64, 44=256, 45=1024
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52=25, 53=125, 54=625, 55=3125
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If they are then placed in numerical order, with any repeats removed, we get the following sequence of 15 distinct terms:
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4, 8, 9, 16, 25, 27, 32, 64, 81, 125, 243, 256, 625, 1024, 3125
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How many distinct terms are in the sequence generated by ab for 2 <= a <= 100 and 2 <= b <= 100?
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"""
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collectPowers = set()
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currentPow = 0
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N = 101 # maximum limit
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for a in range(2,N):
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for b in range (2,N):
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currentPow = a**b # calculates the current power
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collectPowers.add(currentPow) # adds the result to the set
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print "Number of terms ", len(collectPowers)
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if __name__ == '__main__':
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main()
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605
other/primelib.py
Normal file
605
other/primelib.py
Normal file
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@ -0,0 +1,605 @@
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# -*- coding: utf-8 -*-
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"""
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Created on Thu Oct 5 16:44:23 2017
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@author: Christian Bender
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This python library contains some useful functions to deal with
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prime numbers and whole numbers.
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Overview:
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isPrime(number)
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sieveEr(N)
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getPrimeNumbers(N)
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primeFactorization(number)
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greatestPrimeFactor(number)
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smallestPrimeFactor(number)
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getPrime(n)
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getPrimesBetween(pNumber1, pNumber2)
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----
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isEven(number)
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isOdd(number)
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gcd(number1, number2) // greatest common divisor
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kgV(number1, number2) // least common multiple
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getDivisors(number) // all divisors of 'number' inclusive 1, number
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isPerfectNumber(number)
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NEW-FUNCTIONS
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simplifyFraction(numerator, denominator)
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factorial (n) // n!
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fib (n) // calculate the n-th fibonacci term.
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-----
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goldbach(number) // Goldbach's assumption
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"""
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def isPrime(number):
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"""
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input: positive integer 'number'
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returns true if 'number' is prime otherwise false.
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"""
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import math # for function sqrt
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# precondition
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assert isinstance(number,int) and (number >= 0) , \
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"'number' must been an int and positive"
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status = True
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# 0 and 1 are none primes.
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if number <= 1:
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status = False
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for divisor in range(2,int(round(math.sqrt(number)))+1):
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# if 'number' divisible by 'divisor' then sets 'status'
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# of false and break up the loop.
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if number % divisor == 0:
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status = False
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break
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# precondition
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assert isinstance(status,bool), "'status' must been from type bool"
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return status
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# ------------------------------------------
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def sieveEr(N):
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"""
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input: positive integer 'N' > 2
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returns a list of prime numbers from 2 up to N.
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This function implements the algorithm called
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sieve of erathostenes.
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"""
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# precondition
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assert isinstance(N,int) and (N > 2), "'N' must been an int and > 2"
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# beginList: conatins all natural numbers from 2 upt to N
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beginList = [x for x in range(2,N+1)]
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ans = [] # this list will be returns.
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# actual sieve of erathostenes
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for i in range(len(beginList)):
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for j in range(i+1,len(beginList)):
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if (beginList[i] != 0) and \
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(beginList[j] % beginList[i] == 0):
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beginList[j] = 0
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# filters actual prime numbers.
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ans = [x for x in beginList if x != 0]
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# precondition
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assert isinstance(ans,list), "'ans' must been from type list"
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return ans
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# --------------------------------
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def getPrimeNumbers(N):
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"""
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input: positive integer 'N' > 2
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returns a list of prime numbers from 2 up to N (inclusive)
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This function is more efficient as function 'sieveEr(...)'
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"""
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# precondition
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assert isinstance(N,int) and (N > 2), "'N' must been an int and > 2"
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ans = []
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# iterates over all numbers between 2 up to N+1
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# if a number is prime then appends to list 'ans'
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for number in range(2,N+1):
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if isPrime(number):
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ans.append(number)
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# precondition
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assert isinstance(ans,list), "'ans' must been from type list"
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return ans
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# -----------------------------------------
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def primeFactorization(number):
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"""
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input: positive integer 'number'
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returns a list of the prime number factors of 'number'
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"""
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import math # for function sqrt
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# precondition
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assert isinstance(number,int) and number >= 0, \
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"'number' must been an int and >= 0"
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ans = [] # this list will be returns of the function.
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# potential prime number factors.
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factor = 2
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quotient = number
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if number == 0 or number == 1:
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ans.append(number)
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# if 'number' not prime then builds the prime factorization of 'number'
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elif not isPrime(number):
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while (quotient != 1):
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if isPrime(factor) and (quotient % factor == 0):
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ans.append(factor)
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quotient /= factor
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else:
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factor += 1
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else:
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ans.append(number)
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# precondition
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assert isinstance(ans,list), "'ans' must been from type list"
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return ans
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# -----------------------------------------
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def greatestPrimeFactor(number):
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"""
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input: positive integer 'number' >= 0
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returns the greatest prime number factor of 'number'
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"""
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# precondition
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assert isinstance(number,int) and (number >= 0), \
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"'number' bust been an int and >= 0"
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ans = 0
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# prime factorization of 'number'
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primeFactors = primeFactorization(number)
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ans = max(primeFactors)
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# precondition
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assert isinstance(ans,int), "'ans' must been from type int"
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return ans
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# ----------------------------------------------
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def smallestPrimeFactor(number):
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"""
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input: integer 'number' >= 0
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returns the smallest prime number factor of 'number'
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"""
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# precondition
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assert isinstance(number,int) and (number >= 0), \
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"'number' bust been an int and >= 0"
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ans = 0
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# prime factorization of 'number'
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primeFactors = primeFactorization(number)
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ans = min(primeFactors)
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# precondition
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assert isinstance(ans,int), "'ans' must been from type int"
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return ans
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# ----------------------
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def isEven(number):
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"""
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input: integer 'number'
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returns true if 'number' is even, otherwise false.
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"""
|
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|
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# precondition
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assert isinstance(number, int), "'number' must been an int"
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assert isinstance(number % 2 == 0, bool), "compare bust been from type bool"
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return number % 2 == 0
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# ------------------------
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def isOdd(number):
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"""
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input: integer 'number'
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returns true if 'number' is odd, otherwise false.
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"""
|
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|
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# precondition
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assert isinstance(number, int), "'number' must been an int"
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assert isinstance(number % 2 != 0, bool), "compare bust been from type bool"
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return number % 2 != 0
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# ------------------------
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def goldbach(number):
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"""
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Goldbach's assumption
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input: a even positive integer 'number' > 2
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returns a list of two prime numbers whose sum is equal to 'number'
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"""
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# precondition
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assert isinstance(number,int) and (number > 2) and isEven(number), \
|
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"'number' must been an int, even and > 2"
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ans = [] # this list will returned
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# creates a list of prime numbers between 2 up to 'number'
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primeNumbers = getPrimeNumbers(number)
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lenPN = len(primeNumbers)
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# run variable for while-loops.
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i = 0
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j = 1
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# exit variable. for break up the loops
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loop = True
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while (i < lenPN and loop):
|
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j = i+1;
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||||
|
||||
while (j < lenPN and loop):
|
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if primeNumbers[i] + primeNumbers[j] == number:
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loop = False
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ans.append(primeNumbers[i])
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ans.append(primeNumbers[j])
|
||||
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j += 1;
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||||
|
||||
|
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i += 1
|
||||
|
||||
# precondition
|
||||
assert isinstance(ans,list) and (len(ans) == 2) and \
|
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(ans[0] + ans[1] == number) and isPrime(ans[0]) and isPrime(ans[1]), \
|
||||
"'ans' must contains two primes. And sum of elements must been eq 'number'"
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||||
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return ans
|
||||
|
||||
# ----------------------------------------------
|
||||
|
||||
def gcd(number1,number2):
|
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"""
|
||||
Greatest common divisor
|
||||
input: two positive integer 'number1' and 'number2'
|
||||
returns the greatest common divisor of 'number1' and 'number2'
|
||||
"""
|
||||
|
||||
# precondition
|
||||
assert isinstance(number1,int) and isinstance(number2,int) \
|
||||
and (number1 >= 0) and (number2 >= 0), \
|
||||
"'number1' and 'number2' must been positive integer."
|
||||
|
||||
rest = 0
|
||||
|
||||
while number2 != 0:
|
||||
|
||||
rest = number1 % number2
|
||||
number1 = number2
|
||||
number2 = rest
|
||||
|
||||
# precondition
|
||||
assert isinstance(number1,int) and (number1 >= 0), \
|
||||
"'number' must been from type int and positive"
|
||||
|
||||
return number1
|
||||
|
||||
# ----------------------------------------------------
|
||||
|
||||
def kgV(number1, number2):
|
||||
"""
|
||||
Least common multiple
|
||||
input: two positive integer 'number1' and 'number2'
|
||||
returns the least common multiple of 'number1' and 'number2'
|
||||
"""
|
||||
|
||||
# precondition
|
||||
assert isinstance(number1,int) and isinstance(number2,int) \
|
||||
and (number1 >= 1) and (number2 >= 1), \
|
||||
"'number1' and 'number2' must been positive integer."
|
||||
|
||||
ans = 1 # actual answer that will be return.
|
||||
|
||||
# for kgV (x,1)
|
||||
if number1 > 1 and number2 > 1:
|
||||
|
||||
# builds the prime factorization of 'number1' and 'number2'
|
||||
primeFac1 = primeFactorization(number1)
|
||||
primeFac2 = primeFactorization(number2)
|
||||
|
||||
elif number1 == 1 or number2 == 1:
|
||||
|
||||
primeFac1 = []
|
||||
primeFac2 = []
|
||||
ans = max(number1,number2)
|
||||
|
||||
count1 = 0
|
||||
count2 = 0
|
||||
|
||||
done = [] # captured numbers int both 'primeFac1' and 'primeFac2'
|
||||
|
||||
# iterates through primeFac1
|
||||
for n in primeFac1:
|
||||
|
||||
if n not in done:
|
||||
|
||||
if n in primeFac2:
|
||||
|
||||
count1 = primeFac1.count(n)
|
||||
count2 = primeFac2.count(n)
|
||||
|
||||
for i in range(max(count1,count2)):
|
||||
ans *= n
|
||||
|
||||
else:
|
||||
|
||||
count1 = primeFac1.count(n)
|
||||
|
||||
for i in range(count1):
|
||||
ans *= n
|
||||
|
||||
done.append(n)
|
||||
|
||||
# iterates through primeFac2
|
||||
for n in primeFac2:
|
||||
|
||||
if n not in done:
|
||||
|
||||
count2 = primeFac2.count(n)
|
||||
|
||||
for i in range(count2):
|
||||
ans *= n
|
||||
|
||||
done.append(n)
|
||||
|
||||
# precondition
|
||||
assert isinstance(ans,int) and (ans >= 0), \
|
||||
"'ans' must been from type int and positive"
|
||||
|
||||
return ans
|
||||
|
||||
# ----------------------------------
|
||||
|
||||
def getPrime(n):
|
||||
"""
|
||||
Gets the n-th prime number.
|
||||
input: positive integer 'n' >= 0
|
||||
returns the n-th prime number, beginning at index 0
|
||||
"""
|
||||
|
||||
# precondition
|
||||
assert isinstance(n,int) and (n >= 0), "'number' must been a positive int"
|
||||
|
||||
index = 0
|
||||
ans = 2 # this variable holds the answer
|
||||
|
||||
while index < n:
|
||||
|
||||
index += 1
|
||||
|
||||
ans += 1 # counts to the next number
|
||||
|
||||
# if ans not prime then
|
||||
# runs to the next prime number.
|
||||
while not isPrime(ans):
|
||||
ans += 1
|
||||
|
||||
# precondition
|
||||
assert isinstance(ans,int) and isPrime(ans), \
|
||||
"'ans' must been a prime number and from type int"
|
||||
|
||||
return ans
|
||||
|
||||
# ---------------------------------------------------
|
||||
|
||||
def getPrimesBetween(pNumber1, pNumber2):
|
||||
"""
|
||||
input: prime numbers 'pNumber1' and 'pNumber2'
|
||||
pNumber1 < pNumber2
|
||||
returns a list of all prime numbers between 'pNumber1' (exclusiv)
|
||||
and 'pNumber2' (exclusiv)
|
||||
"""
|
||||
|
||||
# precondition
|
||||
assert isPrime(pNumber1) and isPrime(pNumber2) and (pNumber1 < pNumber2), \
|
||||
"The arguments must been prime numbers and 'pNumber1' < 'pNumber2'"
|
||||
|
||||
number = pNumber1 + 1 # jump to the next number
|
||||
|
||||
ans = [] # this list will be returns.
|
||||
|
||||
# if number is not prime then
|
||||
# fetch the next prime number.
|
||||
while not isPrime(number):
|
||||
number += 1
|
||||
|
||||
while number < pNumber2:
|
||||
|
||||
ans.append(number)
|
||||
|
||||
number += 1
|
||||
|
||||
# fetch the next prime number.
|
||||
while not isPrime(number):
|
||||
number += 1
|
||||
|
||||
# precondition
|
||||
assert isinstance(ans,list) and ans[0] != pNumber1 \
|
||||
and ans[len(ans)-1] != pNumber2, \
|
||||
"'ans' must been a list without the arguments"
|
||||
|
||||
# 'ans' contains not 'pNumber1' and 'pNumber2' !
|
||||
return ans
|
||||
|
||||
# ----------------------------------------------------
|
||||
|
||||
def getDivisors(n):
|
||||
"""
|
||||
input: positive integer 'n' >= 1
|
||||
returns all divisors of n (inclusive 1 and 'n')
|
||||
"""
|
||||
|
||||
# precondition
|
||||
assert isinstance(n,int) and (n >= 1), "'n' must been int and >= 1"
|
||||
|
||||
from math import sqrt
|
||||
|
||||
ans = [] # will be returned.
|
||||
|
||||
for divisor in range(1,n+1):
|
||||
|
||||
if n % divisor == 0:
|
||||
ans.append(divisor)
|
||||
|
||||
|
||||
#precondition
|
||||
assert ans[0] == 1 and ans[len(ans)-1] == n, \
|
||||
"Error in function getDivisiors(...)"
|
||||
|
||||
|
||||
return ans
|
||||
|
||||
|
||||
# ----------------------------------------------------
|
||||
|
||||
|
||||
def isPerfectNumber(number):
|
||||
"""
|
||||
input: positive integer 'number' > 1
|
||||
returns true if 'number' is a perfect number otherwise false.
|
||||
"""
|
||||
|
||||
# precondition
|
||||
assert isinstance(number,int) and (number > 1), \
|
||||
"'number' must been an int and >= 1"
|
||||
|
||||
divisors = getDivisors(number)
|
||||
|
||||
# precondition
|
||||
assert isinstance(divisors,list) and(divisors[0] == 1) and \
|
||||
(divisors[len(divisors)-1] == number), \
|
||||
"Error in help-function getDivisiors(...)"
|
||||
|
||||
# summed all divisors up to 'number' (exclusive), hence [:-1]
|
||||
return sum(divisors[:-1]) == number
|
||||
|
||||
# ------------------------------------------------------------
|
||||
|
||||
def simplifyFraction(numerator, denominator):
|
||||
"""
|
||||
input: two integer 'numerator' and 'denominator'
|
||||
assumes: 'denominator' != 0
|
||||
returns: a tuple with simplify numerator and denominator.
|
||||
"""
|
||||
|
||||
# precondition
|
||||
assert isinstance(numerator, int) and isinstance(denominator,int) \
|
||||
and (denominator != 0), \
|
||||
"The arguments must been from type int and 'denominator' != 0"
|
||||
|
||||
# build the greatest common divisor of numerator and denominator.
|
||||
gcdOfFraction = gcd(abs(numerator), abs(denominator))
|
||||
|
||||
# precondition
|
||||
assert isinstance(gcdOfFraction, int) and (numerator % gcdOfFraction == 0) \
|
||||
and (denominator % gcdOfFraction == 0), \
|
||||
"Error in function gcd(...,...)"
|
||||
|
||||
return (numerator // gcdOfFraction, denominator // gcdOfFraction)
|
||||
|
||||
# -----------------------------------------------------------------
|
||||
|
||||
def factorial(n):
|
||||
"""
|
||||
input: positive integer 'n'
|
||||
returns the factorial of 'n' (n!)
|
||||
"""
|
||||
|
||||
# precondition
|
||||
assert isinstance(n,int) and (n >= 0), "'n' must been a int and >= 0"
|
||||
|
||||
ans = 1 # this will be return.
|
||||
|
||||
for factor in range(1,n+1):
|
||||
ans *= factor
|
||||
|
||||
return ans
|
||||
|
||||
# -------------------------------------------------------------------
|
||||
|
||||
def fib(n):
|
||||
"""
|
||||
input: positive integer 'n'
|
||||
returns the n-th fibonacci term , indexing by 0
|
||||
"""
|
||||
|
||||
# precondition
|
||||
assert isinstance(n, int) and (n >= 0), "'n' must been an int and >= 0"
|
||||
|
||||
tmp = 0
|
||||
fib1 = 1
|
||||
ans = 1 # this will be return
|
||||
|
||||
for i in range(n-1):
|
||||
|
||||
tmp = ans
|
||||
ans += fib1
|
||||
fib1 = tmp
|
||||
|
||||
return ans
|
Loading…
Reference in New Issue
Block a user