Create ActivitySelection (#1384)

* Create ActivitySelection

* Update and rename ActivitySelection to activity_selection.py

* Update activity_selection.py

* Update activity_selection.py

* Update activity_selection.py

* Update activity_selection.py

* Update activity_selection.py

* Update activity_selection.py

* Rename activity_selection.py to other/activity_selection.py

* Update activity_selection.py

* Update activity_selection.py

* Add a doctest

* print(j, end=" ")

* print(i, end=" ")

* colons

* Add trailing space
This commit is contained in:
Swati Prajapati 2019-10-19 03:13:33 +05:30 committed by Christian Clauss
parent 43f99e56c9
commit 8366782688

View File

@ -0,0 +1,43 @@
"""The following implementation assumes that the activities
are already sorted according to their finish time"""
"""Prints a maximum set of activities that can be done by a
single person, one at a time"""
# n --> Total number of activities
# start[]--> An array that contains start time of all activities
# finish[] --> An array that contains finish time of all activities
def printMaxActivities(start, finish):
"""
>>> start = [1, 3, 0, 5, 8, 5]
>>> finish = [2, 4, 6, 7, 9, 9]
>>> printMaxActivities(start, finish)
The following activities are selected:
0 1 3 4
"""
n = len(finish)
print("The following activities are selected:")
# The first activity is always selected
i = 0
print(i, end=" ")
# Consider rest of the activities
for j in range(n):
# If this activity has start time greater than
# or equal to the finish time of previously
# selected activity, then select it
if start[j] >= finish[i]:
print(j, end=" ")
i = j
# Driver program to test above function
start = [1, 3, 0, 5, 8, 5]
finish = [2, 4, 6, 7, 9, 9]
printMaxActivities(start, finish)
"""
The following activities are selected:
0 1 3 4
"""