added solution 7 for problem_01 (#1416)

* added solution 7 for problem_01

* added solution 5 for problem_02
This commit is contained in:
Suad Djelili 2019-10-22 10:31:17 +03:00 committed by Christian Clauss
parent ce7faa5a3a
commit 8b572e6cfd
2 changed files with 78 additions and 0 deletions

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"""
Problem Statement:
If we list all the natural numbers below 10 that are multiples of 3 or 5,
we get 3,5,6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below N.
"""
def solution(n):
"""Returns the sum of all the multiples of 3 or 5 below n.
>>> solution(3)
0
>>> solution(4)
3
>>> solution(10)
23
>>> solution(600)
83700
"""
result = 0
for i in range(n):
if i % 3 == 0:
result += i
elif i % 5 == 0:
result += i
return result
if __name__ == "__main__":
print(solution(int(input().strip())))

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"""
Problem:
Each new term in the Fibonacci sequence is generated by adding the previous two
terms. By starting with 1 and 2, the first 10 terms will be:
1,2,3,5,8,13,21,34,55,89,..
By considering the terms in the Fibonacci sequence whose values do not exceed
n, find the sum of the even-valued terms. e.g. for n=10, we have {2,8}, sum is
10.
"""
def solution(n):
"""Returns the sum of all fibonacci sequence even elements that are lower
or equals to n.
>>> solution(10)
10
>>> solution(15)
10
>>> solution(2)
2
>>> solution(1)
0
>>> solution(34)
44
"""
a = [0,1]
i = 0
while a[i] <= n:
a.append(a[i] + a[i+1])
if a[i+2] > n:
break
i += 1
sum = 0
for j in range(len(a) - 1):
if a[j] % 2 == 0:
sum += a[j]
return sum
if __name__ == "__main__":
print(solution(int(input().strip())))