Cleanup Project Euler Problem 01 (#2900)

* mv str statement into docstr

* rename var to avoid redefining builtin

* clean up module docstr
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Carlos Meza 2020-10-09 22:33:00 -07:00 committed by GitHub
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commit 927e14e7f2
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7 changed files with 22 additions and 23 deletions

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@ -1,7 +1,7 @@
"""
Problem Statement:
If we list all the natural numbers below 10 that are multiples of 3 or 5,
we get 3,5,6 and 9. The sum of these multiples is 23.
we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below N.
"""

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@ -1,7 +1,7 @@
"""
Problem Statement:
If we list all the natural numbers below 10 that are multiples of 3 or 5,
we get 3,5,6 and 9. The sum of these multiples is 23.
we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below N.
"""
@ -19,14 +19,14 @@ def solution(n: int = 1000) -> int:
83700
"""
sum = 0
total = 0
terms = (n - 1) // 3
sum += ((terms) * (6 + (terms - 1) * 3)) // 2 # sum of an A.P.
total += ((terms) * (6 + (terms - 1) * 3)) // 2 # total of an A.P.
terms = (n - 1) // 5
sum += ((terms) * (10 + (terms - 1) * 5)) // 2
total += ((terms) * (10 + (terms - 1) * 5)) // 2
terms = (n - 1) // 15
sum -= ((terms) * (30 + (terms - 1) * 15)) // 2
return sum
total -= ((terms) * (30 + (terms - 1) * 15)) // 2
return total
if __name__ == "__main__":

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@ -1,7 +1,7 @@
"""
Problem Statement:
If we list all the natural numbers below 10 that are multiples of 3 or 5,
we get 3,5,6 and 9. The sum of these multiples is 23.
we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below N.
"""
@ -22,38 +22,38 @@ def solution(n: int = 1000) -> int:
83700
"""
sum = 0
total = 0
num = 0
while 1:
num += 3
if num >= n:
break
sum += num
total += num
num += 2
if num >= n:
break
sum += num
total += num
num += 1
if num >= n:
break
sum += num
total += num
num += 3
if num >= n:
break
sum += num
total += num
num += 1
if num >= n:
break
sum += num
total += num
num += 2
if num >= n:
break
sum += num
total += num
num += 3
if num >= n:
break
sum += num
return sum
total += num
return total
if __name__ == "__main__":

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@ -1,7 +1,7 @@
"""
Problem Statement:
If we list all the natural numbers below 10 that are multiples of 3 or 5,
we get 3,5,6 and 9. The sum of these multiples is 23.
we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below N.
"""

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@ -1,15 +1,14 @@
"""
Problem Statement:
If we list all the natural numbers below 10 that are multiples of 3 or 5,
we get 3,5,6 and 9. The sum of these multiples is 23.
we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below N.
"""
"""A straightforward pythonic solution using list comprehension"""
def solution(n: int = 1000) -> int:
"""Returns the sum of all the multiples of 3 or 5 below n.
A straightforward pythonic solution using list comprehension.
>>> solution(3)
0

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@ -1,7 +1,7 @@
"""
Problem Statement:
If we list all the natural numbers below 10 that are multiples of 3 or 5,
we get 3,5,6 and 9. The sum of these multiples is 23.
we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below N.
"""

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@ -1,7 +1,7 @@
"""
Problem Statement:
If we list all the natural numbers below 10 that are multiples of 3 or 5,
we get 3,5,6 and 9. The sum of these multiples is 23.
we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below N.
"""