mirror of
https://github.com/TheAlgorithms/Python.git
synced 2024-11-28 07:21:07 +00:00
Merge pull request #279 from daniel-s-ingram/master
Solution to Problem 53
This commit is contained in:
commit
9319981067
36
Project Euler/Problem 53/sol1.py
Normal file
36
Project Euler/Problem 53/sol1.py
Normal file
|
@ -0,0 +1,36 @@
|
|||
#-.- coding: latin-1 -.-
|
||||
from __future__ import print_function
|
||||
from math import factorial
|
||||
'''
|
||||
Combinatoric selections
|
||||
Problem 53
|
||||
|
||||
There are exactly ten ways of selecting three from five, 12345:
|
||||
|
||||
123, 124, 125, 134, 135, 145, 234, 235, 245, and 345
|
||||
|
||||
In combinatorics, we use the notation, 5C3 = 10.
|
||||
|
||||
In general,
|
||||
|
||||
nCr = n!/(r!(n−r)!),where r ≤ n, n! = n×(n−1)×...×3×2×1, and 0! = 1.
|
||||
It is not until n = 23, that a value exceeds one-million: 23C10 = 1144066.
|
||||
|
||||
How many, not necessarily distinct, values of nCr, for 1 ≤ n ≤ 100, are greater than one-million?
|
||||
'''
|
||||
try:
|
||||
xrange #Python 2
|
||||
except NameError:
|
||||
xrange = range #Python 3
|
||||
|
||||
def combinations(n, r):
|
||||
return factorial(n)/(factorial(r)*factorial(n-r))
|
||||
|
||||
total = 0
|
||||
|
||||
for i in xrange(1, 101):
|
||||
for j in xrange(1, i+1):
|
||||
if combinations(i, j) > 1e6:
|
||||
total += 1
|
||||
|
||||
print(total)
|
Loading…
Reference in New Issue
Block a user