Add Project Euler problem 117 solution 1 (#6872)

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* [Sol1](project_euler/problem_115/sol1.py)
* Problem 116
* [Sol1](project_euler/problem_116/sol1.py)
* Problem 117
* [Sol1](project_euler/problem_117/sol1.py)
* Problem 119
* [Sol1](project_euler/problem_119/sol1.py)
* Problem 120

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"""
Project Euler Problem 117: https://projecteuler.net/problem=117
Using a combination of grey square tiles and oblong tiles chosen from:
red tiles (measuring two units), green tiles (measuring three units),
and blue tiles (measuring four units),
it is possible to tile a row measuring five units in length
in exactly fifteen different ways.
|grey|grey|grey|grey|grey| |red,red|grey|grey|grey|
|grey|red,red|grey|grey| |grey|grey|red,red|grey|
|grey|grey|grey|red,red| |red,red|red,red|grey|
|red,red|grey|red,red| |grey|red,red|red,red|
|green,green,green|grey|grey| |grey|green,green,green|grey|
|grey|grey|green,green,green| |red,red|green,green,green|
|green,green,green|red,red| |blue,blue,blue,blue|grey|
|grey|blue,blue,blue,blue|
How many ways can a row measuring fifty units in length be tiled?
NOTE: This is related to Problem 116 (https://projecteuler.net/problem=116).
"""
def solution(length: int = 50) -> int:
"""
Returns the number of ways can a row of the given length be tiled
>>> solution(5)
15
"""
ways_number = [1] * (length + 1)
for row_length in range(length + 1):
for tile_length in range(2, 5):
for tile_start in range(row_length - tile_length + 1):
ways_number[row_length] += ways_number[
row_length - tile_start - tile_length
]
return ways_number[length]
if __name__ == "__main__":
print(f"{solution() = }")