Merge branch 'master' into levenshtein_distance

This commit is contained in:
Kelvin Salton do Prado 2018-10-02 21:12:16 -03:00
commit 9aea2bc539
2 changed files with 67 additions and 0 deletions

16
Maths/fibonacciSeries.py Normal file
View File

@ -0,0 +1,16 @@
# Fibonacci Sequence Using Recursion
def recur_fibo(n):
if n <= 1:
return n
else:
return(recur_fibo(n-1) + recur_fibo(n-2))
limit = int(input("How many terms to include in fionacci series:"))
if limit <= 0:
print("Plese enter a positive integer")
else:
print("Fibonacci series:")
for i in range(limit):
print(recur_fibo(i))

View File

@ -0,0 +1,51 @@
'''
The stock span problem is a financial problem where we have a series of n daily
price quotes for a stock and we need to calculate span of stocks price for all n days.
The span Si of the stocks price on a given day i is defined as the maximum
number of consecutive days just before the given day, for which the price of the stock
on the current day is less than or equal to its price on the given day.
'''
def calculateSpan(price, S):
n = len(price)
# Create a stack and push index of fist element to it
st = []
st.append(0)
# Span value of first element is always 1
S[0] = 1
# Calculate span values for rest of the elements
for i in range(1, n):
# Pop elements from stack whlie stack is not
# empty and top of stack is smaller than price[i]
while( len(st) > 0 and price[st[0]] <= price[i]):
st.pop()
# If stack becomes empty, then price[i] is greater
# than all elements on left of it, i.e. price[0],
# price[1], ..price[i-1]. Else the price[i] is
# greater than elements after top of stack
S[i] = i+1 if len(st) <= 0 else (i - st[0])
# Push this element to stack
st.append(i)
# A utility function to print elements of array
def printArray(arr, n):
for i in range(0,n):
print arr[i],
# Driver program to test above function
price = [10, 4, 5, 90, 120, 80]
S = [0 for i in range(len(price)+1)]
# Fill the span values in array S[]
calculateSpan(price, S)
# Print the calculated span values
printArray(S, len(price))