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bin_to_octal (#2431)

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* bin_to_octal

Converts binary values to the octal equivalent.

* Update bin_to_octal

* Update conversions/bin_to_octal

Co-authored-by: Christian Clauss <cclauss@me.com>

* Update conversions/bin_to_octal

Co-authored-by: Du Yuanchao <shellhub.me@gmail.com>

* Update conversions/bin_to_octal

Co-authored-by: Du Yuanchao <shellhub.me@gmail.com>

* Update conversions/bin_to_octal

Co-authored-by: Du Yuanchao <shellhub.me@gmail.com>

* Rename bin_to_octal to bin_to_octal.py

Co-authored-by: Christian Clauss <cclauss@me.com>
Co-authored-by: Du Yuanchao <shellhub.me@gmail.com>
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mohammadreza490 2020-09-19 06:36:56 +01:00 committed by GitHub
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conversions/bin_to_octal.py Normal file
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"""
The function below will convert any binary string to the octal equivalent.
>>> bin_to_octal("1111")
'17'
>>> bin_to_octal("101010101010011")
'52523'
>>> bin_to_octal("")
Traceback (most recent call last):
...
ValueError: Empty string was passed to the function
>>> bin_to_octal("a-1")
Traceback (most recent call last):
...
ValueError: Non-binary value was passed to the function
"""
def bin_to_octal(bin_string: str) -> str:
if not all(char in "01" for char in bin_string):
raise ValueError("Non-binary value was passed to the function")
if not bin_string:
raise ValueError("Empty string was passed to the function")
oct_string = ""
while len(bin_string) % 3 != 0:
bin_string = "0" + bin_string
bin_string_in_3_list = [
bin_string[index: index + 3]
for index, value in enumerate(bin_string)
if index % 3 == 0
]
for bin_group in bin_string_in_3_list:
oct_val = 0
for index, val in enumerate(bin_group):
oct_val += int(2 ** (2 - index) * int(val))
oct_string += str(oct_val)
return oct_string
if __name__ == "__main__":
from doctest import testmod
testmod()