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Re-design psnr.py code and change image names (#592)
* Change some Image File names & re-code the psnr algorithm (conserving both methods). Also Added new example. * Selected psnr method and reformat some code from arithmetic_analysis
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analysis/compression_analysis/PSNR-example-base.png
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analysis/compression_analysis/PSNR-example-base.png
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analysis/compression_analysis/PSNR-example-comp-10.jpg
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analysis/compression_analysis/example_wikipedia_image.jpg
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@ -1,38 +1,39 @@
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import numpy as np
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"""
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Peak signal-to-noise ratio - PSNR - https://en.wikipedia.org/wiki/Peak_signal-to-noise_ratio
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Soruce: https://tutorials.techonical.com/how-to-calculate-psnr-value-of-two-images-using-python/
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"""
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import math
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import cv2
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import numpy as np
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def Representational(r,g,b):
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return (0.299*r+0.287*g+0.114*b)
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def psnr(original, contrast):
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mse = np.mean((original - contrast) ** 2)
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if mse == 0:
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return 100
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PIXEL_MAX = 255.0
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PSNR = 20 * math.log10(PIXEL_MAX / math.sqrt(mse))
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return PSNR
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def calculate(img):
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b,g,r = cv2.split(img)
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pixelAt = Representational(r,g,b)
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return pixelAt
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def main():
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#Loading images (orignal image and compressed image)
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orignal_image = cv2.imread('orignal_image.png',1)
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compressed_image = cv2.imread('compressed_image.png',1)
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#Getting image height and width
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height,width = orignal_image.shape[:2]
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# Loading images (original image and compressed image)
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original = cv2.imread('original_image.png')
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contrast = cv2.imread('compressed_image.png', 1)
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orignalPixelAt = calculate(orignal_image)
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compressedPixelAt = calculate(compressed_image)
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original2 = cv2.imread('PSNR-example-base.png')
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contrast2 = cv2.imread('PSNR-example-comp-10.jpg', 1)
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diff = orignalPixelAt - compressedPixelAt
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error = np.sum(np.abs(diff) ** 2)
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error = error/(height*width)
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#MSR = error_sum/(height*width)
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PSNR = -(10*math.log10(error/(255*255)))
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print("PSNR value is {}".format(PSNR))
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# Value expected: 29.73dB
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print("-- First Test --")
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print(f"PSNR value is {psnr(original, contrast)} dB")
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# # Value expected: 31.53dB (Wikipedia Example)
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print("\n-- Second Test --")
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print(f"PSNR value is {psnr(original2, contrast2)} dB")
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if __name__ == '__main__':
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main()
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main()
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@ -15,7 +15,7 @@ def bisection(function, a, b): # finds where the function becomes 0 in [a,b] us
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return
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else:
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mid = (start + end) / 2
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while abs(start - mid) > 0.0000001: # until we achieve precise equals to 10^-7
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while abs(start - mid) > 10**-7: # until we achieve precise equals to 10^-7
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if function(mid) == 0:
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return mid
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elif function(mid) * function(start) < 0:
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@ -29,5 +29,5 @@ def bisection(function, a, b): # finds where the function becomes 0 in [a,b] us
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def f(x):
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return math.pow(x, 3) - 2*x - 5
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print(bisection(f, 1, 1000))
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if __name__ == "__main__":
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print(bisection(f, 1, 1000))
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@ -5,12 +5,13 @@ def intersection(function,x0,x1): #function is the f we want to find its root an
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x_n1 = x1
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while True:
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x_n2 = x_n1-(function(x_n1)/((function(x_n1)-function(x_n))/(x_n1-x_n)))
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if abs(x_n2 - x_n1)<0.00001 :
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if abs(x_n2 - x_n1) < 10**-5:
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return x_n2
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x_n=x_n1
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x_n1=x_n2
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def f(x):
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return math.pow(x,3)-2*x-5
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return math.pow(x , 3) - (2 * x) -5
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print(intersection(f,3,3.5))
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if __name__ == "__main__":
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print(intersection(f,3,3.5))
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@ -1,13 +1,14 @@
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# lower–upper (LU) decomposition - https://en.wikipedia.org/wiki/LU_decomposition
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import numpy
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def LUDecompose (table):
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#table that contains our data
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#table has to be a square array so we need to check first
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# Table that contains our data
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# Table has to be a square array so we need to check first
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rows,columns=numpy.shape(table)
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L=numpy.zeros((rows,columns))
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U=numpy.zeros((rows,columns))
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if rows!=columns:
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return
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return []
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for i in range (columns):
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for j in range(i-1):
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sum=0
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@ -22,13 +23,10 @@ def LUDecompose (table):
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U[i][j]=table[i][j]-sum1
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return L,U
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matrix =numpy.array([[2,-2,1],[0,1,2],[5,3,1]])
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L,U = LUDecompose(matrix)
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print(L)
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print(U)
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if __name__ == "__main__":
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matrix =numpy.array([[2,-2,1],
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[0,1,2],
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[5,3,1]])
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L,U = LUDecompose(matrix)
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print(L)
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print(U)
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@ -1,15 +1,18 @@
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# Newton's Method - https://en.wikipedia.org/wiki/Newton%27s_method
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def newton(function,function1,startingInt): #function is the f(x) and function1 is the f'(x)
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x_n=startingInt
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while True:
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x_n1=x_n-function(x_n)/function1(x_n)
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if abs(x_n-x_n1)<0.00001:
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if abs(x_n-x_n1) < 10**-5:
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return x_n1
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x_n=x_n1
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def f(x):
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return (x**3)-2*x-5
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return (x**3) - (2 * x) -5
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def f1(x):
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return 3*(x**2)-2
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return 3 * (x**2) -2
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print(newton(f,f1,3))
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if __name__ == "__main__":
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print(newton(f,f1,3))
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@ -21,7 +21,7 @@ def minDist(mdist, vset, V):
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def Dijkstra(graph, V, src):
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mdist=[float('inf') for i in range(V)]
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vset = [False for i in range(V)]
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mdist[src] = 0.0;
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mdist[src] = 0.0
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for i in range(V-1):
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u = minDist(mdist, vset, V)
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