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I documented the md5 hash
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@ -10,6 +10,13 @@ def rearrange(bitString32):
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return newString
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def reformatHex(i):
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"""[summary]
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Converts the given integer into 8-digit hex number.
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Arguments:
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i {[int]} -- [integer]
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"""
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hexrep = format(i,'08x')
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thing = ""
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for i in [3,2,1,0]:
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@ -17,6 +24,16 @@ def reformatHex(i):
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return thing
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def pad(bitString):
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"""[summary]
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Fills up the binary string to a 512 bit binary string
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Arguments:
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bitString {[string]} -- [binary string]
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Returns:
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[string] -- [binary string]
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"""
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startLength = len(bitString)
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bitString += '1'
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while len(bitString) % 512 != 448:
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@ -26,6 +43,15 @@ def pad(bitString):
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return bitString
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def getBlock(bitString):
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"""[summary]
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Iterator:
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Returns by each call a list of length 16 with the 32 bit
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integer blocks.
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Arguments:
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bitString {[string]} -- [binary string >= 512]
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"""
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currPos = 0
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while currPos < len(bitString):
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currPart = bitString[currPos:currPos+512]
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@ -34,6 +60,7 @@ def getBlock(bitString):
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mySplits.append(int(rearrange(currPart[32*i:32*i+32]),2))
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yield mySplits
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currPos += 512
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def not32(i):
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i_str = format(i,'032b')
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new_str = ''
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@ -48,6 +75,13 @@ def leftrot32(i,s):
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return (i << s) ^ (i >> (32-s))
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def md5me(testString):
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"""[summary]
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Returns a 32-bit hash code of the string 'testString'
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Arguments:
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testString {[string]} -- [message]
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"""
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bs =''
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for i in testString:
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bs += format(ord(i),'08b')
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