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Modified doctest
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@ -1,6 +1,3 @@
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# https://en.wikipedia.org/wiki/Lowest_common_ancestor
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# https://en.wikipedia.org/wiki/Breadth-first_search
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from __future__ import annotations
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from queue import Queue
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@ -26,8 +23,12 @@ def create_sparse(max_node: int, parent: list[list[int]]) -> list[list[int]]:
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"""
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Create a sparse table that saves each node's 2^i-th parent.
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The given `parent` table should have the direct parent of each node in row 0.
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The function then fills in parent[j][i] = parent[j-1][parent[j-1][i]] for each j where 2^j < max_node.
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The given ``parent`` table should have the direct parent of each node in row 0.
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This function fills in:
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parent[j][i] = parent[j - 1][parent[j - 1][i]]
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for each j where 2^j is less than max_node.
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For example, consider a small tree where:
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- Node 1 is the root (its parent is 0),
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@ -36,18 +37,12 @@ def create_sparse(max_node: int, parent: list[list[int]]) -> list[list[int]]:
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We set up the parent table for only two levels (row 0 and row 1)
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for max_node = 3. (Note that in practice the table has many rows.)
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>>> # Create an initial parent table with 2 rows and indices 0..3.
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>>> parent0 = [0, 0, 1, 1] # 0 is unused; node1's parent=0, node2 and 3's parent=1.
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>>> parent0 = [0, 0, 1, 1] # 0 is unused; node1's parent=0, nodes 2 and 3's parent=1.
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>>> parent1 = [0, 0, 0, 0]
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>>> parent = [parent0, parent1]
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>>> # We need at least (1 << j) < max_node holds only for j = 1 here since (1 << 1)=2 < 3 and (1 << 2)=4 !< 3.
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>>> sparse = create_sparse(3, parent)
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>>> sparse[1][1], sparse[1][2], sparse[1][3]
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>>> (sparse[1][1], sparse[1][2], sparse[1][3])
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(0, 0, 0)
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>>> # Explanation:
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>>> # For node 1: parent[1][1] = parent[0][parent[0][1]] = parent[0][0] = 0.
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>>> # For node 2: parent[1][2] = parent[0][parent[0][2]] = parent[0][1] = 0.
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>>> # For node 3: parent[1][3] = parent[0][parent[0][3]] = parent[0][1] = 0.
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"""
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j = 1
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while (1 << j) < max_node:
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@ -63,19 +58,19 @@ def lowest_common_ancestor(
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"""
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Return the lowest common ancestor (LCA) of nodes u and v in a tree.
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The lists `level` and `parent` must be precomputed. `level[i]` is the depth of node i,
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and `parent` is a sparse table where parent[0][i] is the direct parent of node i.
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The lists ``level`` and ``parent`` must be precomputed. ``level[i]`` is the depth
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of node i, and ``parent`` is a sparse table where parent[0][i] is the direct parent
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of node i.
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>>> # Consider a simple tree:
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>>> # 1
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>>> # / \\
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>>> # 2 3
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>>> # With levels: level[1]=0, level[2]=1, level[3]=1 and parent[0]=[0,0,1,1]
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>>> # With levels: level[1]=0, level[2]=1, level[3]=1 and parent[0]=[0, 0, 1, 1]
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>>> level = [-1, 0, 1, 1] # index 0 is dummy
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>>> parent = [[0, 0, 1, 1]] + [[0, 0, 0, 0] for _ in range(19)]
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>>> lowest_common_ancestor(2, 3, level, parent)
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1
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>>> # LCA of a node with itself is itself.
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>>> lowest_common_ancestor(2, 2, level, parent)
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2
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"""
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@ -93,7 +88,6 @@ def lowest_common_ancestor(
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for i in range(18, -1, -1):
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if parent[i][u] not in [0, parent[i][v]]:
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u, v = parent[i][u], parent[i][v]
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# Return the parent (direct ancestor) which is the LCA.
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return parent[0][u]
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@ -107,8 +101,8 @@ def breadth_first_search(
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"""
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Run a breadth-first search (BFS) from the root node of the tree.
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Sets every node's direct parent (in parent[0]) and calculates the depth (level)
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of each node from the root.
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This sets each node's direct parent (stored in parent[0]) and calculates the
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depth (level) of each node from the root.
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>>> # Consider a simple tree:
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>>> # 1
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@ -138,8 +132,8 @@ def breadth_first_search(
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def main() -> None:
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"""
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Run a BFS to set node depths and parents in a sample tree,
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then create the sparse table and compute several lowest common ancestors.
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Run a BFS to set node depths and parents in a sample tree, then create the
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sparse table and compute several lowest common ancestors.
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The sample tree used is:
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@ -174,9 +168,7 @@ def main() -> None:
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True
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"""
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max_node = 13
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# initializing with 0; extra space is allocated.
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parent = [[0 for _ in range(max_node + 10)] for _ in range(20)]
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# initializing with -1 which means every node is unvisited.
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level = [-1 for _ in range(max_node + 10)]
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graph: dict[int, list[int]] = {
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1: [2, 3, 4],
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