Arunsiva003 patch 1 flatten tree (#9695)

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---------

Co-authored-by: ArunSiva <Arunsiva003@users.noreply.github.com>
Co-authored-by: pre-commit-ci[bot] <66853113+pre-commit-ci[bot]@users.noreply.github.com>
Co-authored-by: Christian Clauss <cclauss@me.com>
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"""
Binary Tree Flattening Algorithm
This code defines an algorithm to flatten a binary tree into a linked list
represented using the right pointers of the tree nodes. It uses in-place
flattening and demonstrates the flattening process along with a display
function to visualize the flattened linked list.
https://www.geeksforgeeks.org/flatten-a-binary-tree-into-linked-list
Author: Arunkumar A
Date: 04/09/2023
"""
from __future__ import annotations
class TreeNode:
"""
A TreeNode has data variable and pointers to TreeNode objects
for its left and right children.
"""
def __init__(self, data: int) -> None:
self.data = data
self.left: TreeNode | None = None
self.right: TreeNode | None = None
def build_tree() -> TreeNode:
"""
Build and return a sample binary tree.
Returns:
TreeNode: The root of the binary tree.
Examples:
>>> root = build_tree()
>>> root.data
1
>>> root.left.data
2
>>> root.right.data
5
>>> root.left.left.data
3
>>> root.left.right.data
4
>>> root.right.right.data
6
"""
root = TreeNode(1)
root.left = TreeNode(2)
root.right = TreeNode(5)
root.left.left = TreeNode(3)
root.left.right = TreeNode(4)
root.right.right = TreeNode(6)
return root
def flatten(root: TreeNode | None) -> None:
"""
Flatten a binary tree into a linked list in-place, where the linked list is
represented using the right pointers of the tree nodes.
Args:
root (TreeNode): The root of the binary tree to be flattened.
Examples:
>>> root = TreeNode(1)
>>> root.left = TreeNode(2)
>>> root.right = TreeNode(5)
>>> root.left.left = TreeNode(3)
>>> root.left.right = TreeNode(4)
>>> root.right.right = TreeNode(6)
>>> flatten(root)
>>> root.data
1
>>> root.right.right is None
False
>>> root.right.right = TreeNode(3)
>>> root.right.right.right is None
True
"""
if not root:
return
# Flatten the left subtree
flatten(root.left)
# Save the right subtree
right_subtree = root.right
# Make the left subtree the new right subtree
root.right = root.left
root.left = None
# Find the end of the new right subtree
current = root
while current.right:
current = current.right
# Append the original right subtree to the end
current.right = right_subtree
# Flatten the updated right subtree
flatten(right_subtree)
def display_linked_list(root: TreeNode | None) -> None:
"""
Display the flattened linked list.
Args:
root (TreeNode | None): The root of the flattened linked list.
Examples:
>>> root = TreeNode(1)
>>> root.right = TreeNode(2)
>>> root.right.right = TreeNode(3)
>>> display_linked_list(root)
1 2 3
>>> root = None
>>> display_linked_list(root)
"""
current = root
while current:
if current.right is None:
print(current.data, end="")
break
print(current.data, end=" ")
current = current.right
if __name__ == "__main__":
print("Flattened Linked List:")
root = build_tree()
flatten(root)
display_linked_list(root)