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e8b6a8431d
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* [From Sequence](data_structures/linked_list/from_sequence.py)
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* [Has Loop](data_structures/linked_list/has_loop.py)
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* [Is Palindrome](data_structures/linked_list/is_palindrome.py)
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* [Merge Sort Linked List](data_structures/linked_list/merge_sort_linked_list.py)
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* [Merge Two Lists](data_structures/linked_list/merge_two_lists.py)
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* [Middle Element Of Linked List](data_structures/linked_list/middle_element_of_linked_list.py)
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* [Print Reverse](data_structures/linked_list/print_reverse.py)
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155
data_structures/linked_list/merge_sort_linked_list.py
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155
data_structures/linked_list/merge_sort_linked_list.py
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class Node:
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"""
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A class representing a node in a linked list.
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Attributes:
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data (int): The data stored in the node.
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next (Node | None): A reference to the next node in the linked list.
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"""
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def __init__(self, data: int) -> None:
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self.data = data
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self.next: Node | None = None
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def get_middle(head: Node | None) -> Node | None:
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"""
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Find the node before the middle of the linked list
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using the slow and fast pointer technique.
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Parameters:
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head: The head node of the linked list.
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Returns:
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The node before the middle of the linked list,
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or None if the list has fewer than 2 nodes.
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Example:
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>>> head = Node(1)
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>>> head.next = Node(2)
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>>> head.next.next = Node(3)
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>>> middle = get_middle(head)
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>>> middle.data
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2
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"""
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if head is None or head.next is None:
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return None
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slow: Node | None = head
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fast: Node | None = head.next
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while fast is not None and fast.next is not None:
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if slow is None:
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return None
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slow = slow.next
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fast = fast.next.next
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return slow
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def print_linked_list(head: Node | None) -> None:
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"""
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Print the linked list in a single line.
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Parameters:
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head: The head node of the linked list.
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Example:
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>>> head = Node(1)
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>>> head.next = Node(2)
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>>> head.next.next = Node(3)
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>>> print_linked_list(head)
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1 2 3
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"""
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current = head
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first = True # To avoid printing space before the first element
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while current:
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if not first:
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print(" ", end="")
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print(current.data, end="")
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first = False
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current = current.next
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print()
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def merge(left: Node | None, right: Node | None) -> Node | None:
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"""
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Merge two sorted linked lists into one sorted linked list.
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Parameters:
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left: The head of the first sorted linked list.
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right: The head of the second sorted linked list.
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Returns:
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The head of the merged sorted linked list.
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Example:
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>>> left = Node(1)
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>>> left.next = Node(3)
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>>> right = Node(2)
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>>> right.next = Node(4)
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>>> merged = merge(left, right)
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>>> print_linked_list(merged)
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1 2 3 4
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"""
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if left is None:
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return right
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if right is None:
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return left
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if left.data <= right.data:
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result = left
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result.next = merge(left.next, right)
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else:
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result = right
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result.next = merge(left, right.next)
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return result
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def merge_sort_linked_list(head: Node | None) -> Node | None:
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"""
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Sort a linked list using the Merge Sort algorithm.
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Parameters:
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head: The head node of the linked list to be sorted.
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Returns:
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The head node of the sorted linked list.
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Example:
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>>> head = Node(4)
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>>> head.next = Node(2)
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>>> head.next.next = Node(1)
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>>> head.next.next.next = Node(3)
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>>> sorted_head = merge_sort_linked_list(head)
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>>> print_linked_list(sorted_head)
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1 2 3 4
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"""
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# Base Case: 0 or 1 node
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if head is None or head.next is None:
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return head
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# Split the linked list into two halves
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middle = get_middle(head)
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if middle is None or middle.next is None:
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return head
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next_to_middle = middle.next
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middle.next = None # Split the list into two parts
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# Recursively sort both halves
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left = merge_sort_linked_list(head)
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right = merge_sort_linked_list(next_to_middle)
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# Merge sorted halves
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return merge(left, right)
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if __name__ == "__main__":
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import doctest
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doctest.testmod()
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