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Style Improvements for project_euler/problem_26 (#2958)

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* add typehints and docstrings

* add typehint and default value

* add typehint and default value. Removed unused variable.

* do not modifiy the given solution

* add doctests

* update sol1 after running black

* add typehint, docstring, and doctest

* update sol2 after running black

* add full problem statement and solution function with typehint and doctest

* renamed original function instead of adding new one

* don't alter original solution
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Nelson Stoik 2020-10-07 21:22:24 -06:00 committed by GitHub
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commit ef53bbdf5a
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26
project_euler/problem_26/sol1.py
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@ -1,20 +1,38 @@
"""
Euler Problem 26
https://projecteuler.net/problem=26
Problem Statement:
A unit fraction contains 1 in the numerator. The decimal representation of the
unit fractions with denominators 2 to 10 are given:
1/2 = 0.5
1/3 = 0.(3)
1/4 = 0.25
1/5 = 0.2
1/6 = 0.1(6)
1/7 = 0.(142857)
1/8 = 0.125
1/9 = 0.(1)
1/10 = 0.1
Where 0.1(6) means 0.166666..., and has a 1-digit recurring cycle. It can be
seen that 1/7 has a 6-digit recurring cycle.
Find the value of d < 1000 for which 1/d contains the longest recurring cycle
in its decimal fraction part.
"""
def find_digit(numerator: int, digit: int) -> int:
def solution(numerator: int = 1, digit: int = 1000) -> int:
"""
Considering any range can be provided,
because as per the problem, the digit d < 1000
>>> find_digit(1, 10)
>>> solution(1, 10)
7
>>> find_digit(10, 100)
>>> solution(10, 100)
97
>>> find_digit(10, 1000)
>>> solution(10, 1000)
983
"""
the_digit = 1